Workers P and Q can complete a task in 16 days if working together. P alone takes 24 days. If P and Q start the task together, but Q leaves after 4 days, how many more days will P alone take to finish the work?
18 days
P and Q's combined 1-day work \(= \frac{1}{16}\).
P's 1-day work \(= \frac{1}{24}\).
Work done together in 4 days \(= 4 \times \frac{1}{16} = \frac{1}{4}\).
Remaining work \(= 1 - \frac{1}{4} = \frac{3}{4}\).
Days needed by P alone to finish remaining work \(= \frac{3}{4} \div \frac{1}{24} = \frac{3}{4} \times 24 = 18\) days.
Hence, P alone will take 18 more days to finish the work.
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