This problem involves calculating the combined time taken by three individuals (A, B, and C) to complete a task when working together, given their individual completion times.
First, determine the rate at which each person works. The rate is the amount of task completed per day. It's the inverse of the time taken to complete the task alone.
When working together, their rates add up. Find the combined rate by summing their individual rates:
Combined Rate = A's Rate + B's Rate + C's Rate
Combined Rate = $\frac{1}{15} + \frac{1}{20} + \frac{1}{25}$
To add these fractions, find the Least Common Multiple (LCM) of the denominators (15, 20, 25). The LCM is 300.
Combined Rate = $\frac{1 \times 20}{15 \times 20} + \frac{1 \times 15}{20 \times 15} + \frac{1 \times 12}{25 \times 12}$
Combined Rate = $\frac{20}{300} + \frac{15}{300} + \frac{12}{300}$
Combined Rate = $\frac{20 + 15 + 12}{300} = \frac{47}{300}$ task/day.
The time taken to complete the task together is the inverse of their combined rate:
Time Together = $\frac{1}{\text{Combined Rate}}$
Time Together = $\frac{1}{\frac{47}{300}}$
Time Together = $\frac{300}{47}$ days.
Therefore, A, B, and C can complete the task together in $\frac{300}{47}$ days.
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