This problem is a typical work and time question. It requires understanding the relationship between the number of workers (people), the time taken (days), and the resources used (brooms) to complete a task.
The key principle is that the total work ($W$) needed to sweep the floor is constant. The rate of work is influenced by the number of brooms ($B$) used. We assume that the number of people ($P$) is sufficient to operate the brooms effectively (i.e., $P \ge B$ for both scenarios). Therefore, the rate of work is directly proportional to the number of brooms ($B$).
We can express the rate as Rate $= k \times B$, where $k$ is a constant representing the work done per broom per day.
The general formula for work is $W = \text{Rate} \times \text{Time}$. Substituting our rate expression, we get $W = k \times B \times D$. Since the total work ($W$) and the constant $k$ are the same in both situations, we can establish a direct relationship between the number of brooms and the days:
$B_1 \times D_1 = B_2 \times D_2$
Identify the given values from the problem:
Using the derived formula $B_1 \times D_1 = B_2 \times D_2$:
$12 \times 4 = 8 \times D_2$
First, calculate the product on the left side:
$48 = 8 \times D_2$
Next, solve for $D_2$ by dividing both sides of the equation by 8:
$D_2 = \frac{48}{8}$
$D_2 = 6$
It will take 6 days for 8 people to sweep the floor using 8 brooms.
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