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Question

A and B working alone can finish a task in 12 and 16 days respectively. In how many days can the task be finished if they work for one day each alternatively, and A begins the work?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$13\frac{2}{3}$ days

Here's how to solve the problem step-by-step:

1. Calculate Individual Work Rates

  • A's rate: If A finishes the task in 12 days, A completes $\frac{1}{12}$ of the task per day.
  • B's rate: If B finishes the task in 16 days, B completes $\frac{1}{16}$ of the task per day.

2. Calculate Work Done in a 2-Day Cycle

Since they work alternatively and A starts:

  • Day 1: A works, completes $\frac{1}{12}$.
  • Day 2: B works, completes $\frac{1}{16}$.
  • Work done in 2 days = Work by A + Work by B
  • Work = $\frac{1}{12} + \frac{1}{16}$
  • To add these fractions, find a common denominator (LCM of 12 and 16 is 48):
  • Work = $\frac{4}{48} + \frac{3}{48} = \frac{7}{48}$ of the task.

3. Determine Full Cycles Completed

We need to find how many 2-day cycles are needed to complete the task. Calculate the number of cycles ($k$) so that the work done is close to 1 (the whole task).

  • Work per cycle = $\frac{7}{48}$.
  • Let's estimate $k$. Total work needed is 1. $1 \div \frac{7}{48} = \frac{48}{7} \approx 6.85$. This suggests around 6 full cycles.
  • Work done in 6 cycles = $6 \times \frac{7}{48} = \frac{42}{48} = \frac{7}{8}$ of the task.
  • Number of days passed = $6 \text{ cycles} \times 2 \text{ days/cycle} = 12$ days.

4. Calculate Remaining Work

After 12 days, the remaining work is:

  • Remaining Work = $1 - \frac{7}{8} = \frac{1}{8}$ of the task.

5. Calculate Time for Remaining Work

The 13th day begins, and A starts working:

  • Work done by A on Day 13 = $\frac{1}{12}$.
  • Total work completed after 13 days = Work after 12 days + Work on Day 13
  • Total Work = $\frac{7}{8} + \frac{1}{12} = \frac{21}{24} + \frac{2}{24} = \frac{23}{24}$ of the task.
  • Remaining work after Day 13 = $1 - \frac{23}{24} = \frac{1}{24}$ of the task.

The 14th day begins, and it's B's turn:

  • B's rate = $\frac{1}{16}$ per day.
  • Time needed for B to complete the remaining $\frac{1}{24}$ work = $\frac{\text{Remaining Work}}{\text{B's Rate}}$
  • Time = $\frac{1/24}{1/16} = \frac{1}{24} \times 16 = \frac{16}{24} = \frac{2}{3}$ days.

6. Calculate Total Time

Total time = Days from full cycles + Day 13 + Fractional day on Day 14

  • Total Time = $12 \text{ days} + 1 \text{ day} + \frac{2}{3} \text{ days}$
  • Total Time = $13 \frac{2}{3}$ days.
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Important Questions from Time and Work

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  5. lf 12 men can do a work in 20 days, in how many days will the work be done by 15 men-
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