Here's how to solve the problem step-by-step:
Since they work alternatively and A starts:
We need to find how many 2-day cycles are needed to complete the task. Calculate the number of cycles ($k$) so that the work done is close to 1 (the whole task).
After 12 days, the remaining work is:
The 13th day begins, and A starts working:
The 14th day begins, and it's B's turn:
Total time = Days from full cycles + Day 13 + Fractional day on Day 14
Mohan can do a piece of work in 10 days and Sohan in 15 days. They started working together, but after 3 days Mohan left the work . What time will Sohan take to finish the work?
A tank is filled in 8 hours by three taps A, B and C. The tap C is thrice as fast as B and B is twice as fast as A. How much time will pipe B alone take to fill the tank?
Had been one menless, then the number of days required to do a piece of work would have been one more. If the number of Man. Days required to complete the work is 56, how many workers were there?
A can do a piece of work in 16 hours, B and C can do it in 8 hours while A and C can do it 12 hours. How long will B alone take to do it?