Mohan can do a piece of work in 10 days and Sohan in 15 days. They started working together, but after 3 days Mohan left the work . What time will Sohan take to finish the work?
15/2 days
This question involves calculating the time taken to complete a work when individuals work together and then one leaves. We need to determine how long it takes Sohan to finish the remaining portion of the work.
First, let's figure out the rate at which each person works. The rate is the amount of work done per day.
When they work together, their rates add up. The combined work rate is:
Combined Rate = Mohan's Rate + Sohan's Rate
Combined Rate = $\frac{1}{10} + \frac{1}{15}$
To add these fractions, we find a common denominator, which is 30.
Combined Rate = $\frac{3}{30} + \frac{2}{30} = \frac{3+2}{30} = \frac{5}{30} = \frac{1}{6}$ of the work per day.
Mohan and Sohan worked together for 3 days. The total work done during these 3 days is:
Work Done = Combined Rate $\times$ Number of Days
Work Done = $\frac{1}{6} \times 3 = \frac{3}{6} = \frac{1}{2}$ of the work.
After 3 days, half of the work is completed. The remaining work is:
Remaining Work = Total Work - Work Done
Remaining Work = $1 - \frac{1}{2} = \frac{1}{2}$ of the work.
Now, Sohan has to complete the remaining half of the work alone. We know Sohan's work rate is $\frac{1}{15}$ of the work per day.
Time Taken = $\frac{\text{Remaining Work}}{\text{Sohan's Work Rate}}$
Time Taken = $\frac{\frac{1}{2}}{\frac{1}{15}}$
To divide fractions, we multiply by the reciprocal of the divisor:
Time Taken = $\frac{1}{2} \times \frac{15}{1} = \frac{15}{2}$ days.
Therefore, Sohan will take $\frac{15}{2}$ days to finish the remaining work.
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