This problem involves calculating the time taken by an individual worker based on relative efficiency and combined work time.
$W = (\text{Combined Rate}) \times (\text{Time Taken Together}) $
$W = (3r_B) \times 10 \text{ days} = 30r_B \text{ units of work} $
$ \text{Time for A} = \frac{\text{Total Work}}{r_A} $
$ \text{Time for A} = \frac{30r_B}{2r_B} $
$ \text{Time for A} = 15 \text{ days} $
Therefore, A will finish the work alone in 15 days.
Mohan can do a piece of work in 10 days and Sohan in 15 days. They started working together, but after 3 days Mohan left the work . What time will Sohan take to finish the work?
A tank is filled in 8 hours by three taps A, B and C. The tap C is thrice as fast as B and B is twice as fast as A. How much time will pipe B alone take to fill the tank?
Had been one menless, then the number of days required to do a piece of work would have been one more. If the number of Man. Days required to complete the work is 56, how many workers were there?
A can do a piece of work in 16 hours, B and C can do it in 8 hours while A and C can do it 12 hours. How long will B alone take to do it?