First, determine the individual work rates of the father and the son.
They work on alternate days, with the father starting.
Consider a 2-day cycle (Father + Son):
Work done in 2 days = Father's work + Son's work
Work = $\frac{1}{8} + \frac{1}{7} = \frac{7 + 8}{56} = \frac{15}{56}$ of the task.
Calculate the cumulative work done day by day:
At the end of Day 7, $\frac{52}{56}$ of the task is completed.
Remaining work = $1 - \frac{52}{56} = \frac{4}{56} = \frac{1}{14}$ of the task.
Day 8 is the son's turn to work. The son's rate is $\frac{1}{7}$ task per day.
Time needed for the son to complete the remaining work:
Time = $\frac{\text{Remaining Work}}{\text{Son's Rate}} = \frac{1/14}{1/7} = \frac{1}{14} \times 7 = \frac{7}{14} = \frac{1}{2}$ day.
Total time to complete the task = Days completed by Father + Days completed by Son
Total time = 7 days + $\frac{1}{2}$ day = $7 \frac{1}{2}$ days.
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