Match the following: Codes :List - I List - II (a) 
(i) Schmitt trigger circuit (b) 
(ii) Triangular wave generator (c) 
(iii) Subtractor (d) 
(iv) Integrator circuit
(a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
Each circuit is identified by what sits in its feedback path, and by whether that feedback is negative or positive.
(a) Resistor in, capacitor back — the integrator → (iv):
\(V_{o}=-\dfrac{1}{RC}\int V_{in}\,dt\)
(b) The same, but with Rsh across the capacitor — the practical integrator, used here as a triangular wave generator → (ii). Integrating a square wave gives a triangle, since a constant input produces a linear ramp whose slope reverses with the input. The shunt resistor is essential in a real circuit: without it, the op-amp's input offset current would charge the capacitor steadily until the output saturated. Rsh provides a DC feedback path that fixes the operating point, at the cost of making the circuit integrate only above \(f=\dfrac{1}{2\pi R_{sh}C}\).
(c) Feedback to the non-inverting input — the Schmitt trigger → (i). This is positive feedback, so the output cannot rest anywhere but at a saturation rail. The divider sets two trip points:
\(V_{UT},V_{LT}=\pm\dfrac{R_{2}}{R_{1}+R_{2}}V_{sat}\)
and the gap between them is the hysteresis that turns a slow or noisy sine wave into a clean square wave with no chatter at the threshold.
(d) Two inputs, four resistors — the subtractor → (iii). With matched ratios,
\(V_{o}=\dfrac{R_{2}}{R_{1}}\left(V_{in2}-V_{in1}\right)\)
The order (iv), (ii), (i), (iii) is option 1.
| Circuit | Feedback element | Feedback sense | Function |
|---|---|---|---|
| (a) | C | Negative | Integrator |
| (b) | C with shunt R | Negative | Practical integrator / triangle generator |
| (c) | R to + input | Positive | Schmitt trigger |
| (d) | R, both inputs driven | Negative | Subtractor |
The decisive observation is (c)'s feedback terminal. Everything else in the list uses negative feedback and therefore behaves linearly; the moment the feedback resistor returns to the plus input, the circuit becomes a two-state switch. That single wire is what separates an amplifier from a comparator.
The pair (a) and (b) together make the useful point that an integrator and a triangular-wave generator are the same circuit; the difference is only in what drives it and in the DC-stabilising resistor that a real one needs.
Hence, the correct match is (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii).
Similar Questions
Assertion (A) : An Op-Amp is a direct coupled high gain amplifier.
Reason (R) : It consists of one or more differential amplifiers and usually followed by a level translator and push pull stage.
The input to a differentiator is –5 V. Its output will be
Match the following :
List – I List – II a. h-parameters i. O/P voltage varies as the slope of i/p voltage b. differentiator ii. Noise division c. half-wave rectifier iii. Function of a Q point d. integrator iv. series diode clipper Codes :
Assertion (A) : Op-Amp is used for sensor circuit.
Reason (R) : A small signal amplifier amplify weak measured signals.
Consider the following circuit, the switch S1 allows the output to switch between two ranges of amplitudes from 0-0.1 V and 0-1 V. Arrange these values of R1, R2 and R3 in increasing order.
(A) Value of R1
(B) Value of R2
(C) Value of R3Choose the most appropriate answer from the options given below :
The given operational amplifier circuit corresponds to which electronic circuit application ?
Statements in connection to Op-Amp applications are :
A. If we use a square wave generator followed by integrator circuit we get a triangular wave at the output
B. The logarithmic amplifier called a log-amplifier or a logger, is basically a current to voltage converter.
C.
is a first order high pass filter with voltage followerD. If we use a square wave generator followed by a clipping circuit then we get a saw-tooth wave generator.
Choose the correct answer from the options given below:
Match List I with List II
LIST I LIST II A. Single polarity positive voltage clipper circuit I. 
B. Negative clamping circuit II. 
C. Differentiator circuit III. 
D. Logarithmic Amplifier IV. 
Choose the correct answer from the options given below:
The correct flow in the basic block diagram of op-Amp is
A. Complementary symmetry push pull amplifier block.
B. Dual input unbalanced output differential amplifier block
C. Emitter follower with constant current source block
D. Dual-Input balanced output differential amplifier block
Choose the correct answer from the options given below :
Match the following :
List - I List - II a) 
i) 
b) 
ii) 
c) 
iii) 
d) 
iv) 
Codes :
Important Questions from Op-Amp and Its Applications
In the circuit shown below, $R$ is $1\text{ k}\Omega$ and $R_f$ is $10\text{ k}\Omega$. If $V_{\text{in}}$ is $100\text{ mV}$ and the op-amps have supply voltages of $\pm 15\text{ V}$, then $V_{\text{out}}$ is _______ V.
For IC 741 circuit shown below, the maximum input frequency above which the output will be distorted is ____________.
Assume that an op-amp 741 connected as a unit gain inverting amplifier is applied with an input change of 10 V. Determine the time taken for the output to change by 10 V. [Slew rate for op-amp 741 = 0.5 V/µs]
What is the value of output voltage $V_o$ in the given circuit? Assume op-amp to be ideal and MOSFET operating in saturation region.
In an ideal op-amp, the common mode gain is _____________.
