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Question

The core diameter of single mode fiber is in the order of

This question was previously asked in
UGC NET 2014 Paper 1 Question Paper (28-Dec-2014)
The correct answer is

10 µm

 A single-mode core is about 8 to 10 µm across — option 2 — and the figure is not arbitrary; it is fixed by the condition for single-mode operation.

The number of guided modes is governed by the normalised frequency,

\(V=\dfrac{2\pi a}{\lambda}\sqrt{n_{1}^{2}-n_{2}^{2}}=\dfrac{2\pi a}{\lambda}\,NA\)

and only one mode propagates when

\(V\lt2.405\)

the first zero of the Bessel function \(J_{0}\). Put the numbers in for the 1.55 µm window with NA = 0.12:

\(a\lt\dfrac{2.405\times1.55}{2\pi\times0.12}=4.9\ \mu\text{m}\)

a radius of about 5 µm, so a diameter near 10 µm. The answer follows from the operating wavelength and nothing else — which is why the core cannot be shrunk indefinitely.

OptionSizeVerdict
100 µmMultimode / plastic fibre✗ V ≈ 24, many modes
10 µmSingle mode
1 Å0.1 nm — an atom✗ Absurdly sub-wavelength
1 nmA few atoms✗ Same objection

Options 3 and 4 fail on physical grounds, not just numerically. A waveguide much smaller than the wavelength — 1550 nm here — guides nothing; the field is not confined but radiates away. An Ångström is roughly one atomic diameter, so such a "core" could not be built even in principle.

What the small core buys. Only one path exists, so intermodal dispersion vanishes entirely and the bandwidth-distance product rises from a few tens of MHz·km for step-index multimode fibre to tens of THz·km. What it costs is handling: a 9 µm core demands a laser rather than an LED, fusion splicing with sub-micron alignment, and connectors held to comparable tolerance — the reason multimode fibre with its 50 or 62.5 µm core survives for short in-building links.

Hence, the core diameter is of the order of 10 µm.

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Important Questions from Optical Fiber

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