Assertion (A) : An Op-Amp is a direct coupled high gain amplifier. Reason (R) : It consists of one or more differential amplifiers and usually followed by a level translator and push pull stage.
Both (A) and (R) are correct and (R) is correct explanation of (A).
Both statements are true, and the reason gives the internal structure that produces exactly the properties the assertion names — option 1.
The assertion. An operational amplifier is direct coupled — no capacitors between stages — and has a very large open-loop gain, typically \(10^{5}\) to \(10^{6}\), or 100 to 120 dB. Both facts are standard.
The reason explains both. Take the three stages named in turn:
| Stage | Contribution |
|---|---|
| Differential amplifier input | High gain; high common-mode rejection; directly coupled by nature |
| Level translator | Restores the DC level that direct coupling has shifted |
| Push-pull output | Low output impedance, current drive in both directions |
Why the coupling must be direct. An op-amp is required to amplify down to DC — it must respond to a steady difference between its inputs, since that is what integrators, comparators and precision references depend on. A coupling capacitor blocks DC and would destroy this. Direct coupling is therefore not a design convenience but a requirement.
What direct coupling costs, and why the level translator exists. Each stage's output sits at some DC level well above ground, and connecting it straight to the next stage carries that offset forward, accumulating stage by stage until the output is driven towards a rail with no signal applied. The level translator — an emitter follower with a resistor or a constant-current source, or a diode-connected chain — shifts the level back down so that the output rests near zero for zero input. Direct coupling also lets drift and low-frequency noise through, which is why input offset voltage and its temperature drift are prominent specifications.
The differential input does the other essential job : it responds to the difference between the inputs and rejects what is common to both, so hum and supply variation appearing equally on both pins are suppressed — typically by 90 dB or more.
The answer is flagged only because the linkage is a matter of judgement: R describes the construction rather than deducing the properties. But the connection is direct and complete — the differential stages give the gain, and their direct coupling gives the DC response — so R does explain A.
Hence, both (A) and (R) are correct and (R) explains (A).
The input to a differentiator is –5 V. Its output will be
Match the following :
| List – I | List – II |
| a. h-parameters | i. O/P voltage varies as the slope of i/p voltage |
| b. differentiator | ii. Noise division |
| c. half-wave rectifier | iii. Function of a Q point |
| d. integrator | iv. series diode clipper |
Codes :
Assertion (A) : Op-Amp is used for sensor circuit.
Reason (R) : A small signal amplifier amplify weak measured signals.
Consider the following circuit, the switch S1 allows the output to switch between two ranges of amplitudes from 0-0.1 V and 0-1 V. Arrange these values of R1, R2 and R3 in increasing order.

(A) Value of R1
(B) Value of R2
(C) Value of R3
Choose the most appropriate answer from the options given below :
The given operational amplifier circuit corresponds to which electronic circuit application ?

Statements in connection to Op-Amp applications are :
A. If we use a square wave generator followed by integrator circuit we get a triangular wave at the output
B. The logarithmic amplifier called a log-amplifier or a logger, is basically a current to voltage converter.
C.
is a first order high pass filter with voltage follower
D. If we use a square wave generator followed by a clipping circuit then we get a saw-tooth wave generator.
Choose the correct answer from the options given below:
Match List I with List II
| LIST I | LIST II | ||
|---|---|---|---|
| A. | Single polarity positive voltage clipper circuit | I. | ![]() |
| B. | Negative clamping circuit | II. | ![]() |
| C. | Differentiator circuit | III. | ![]() |
| D. | Logarithmic Amplifier | IV. | ![]() |
Choose the correct answer from the options given below:
The correct flow in the basic block diagram of op-Amp is
A. Complementary symmetry push pull amplifier block.
B. Dual input unbalanced output differential amplifier block
C. Emitter follower with constant current source block
D. Dual-Input balanced output differential amplifier block
Choose the correct answer from the options given below :
Match the following :
| List - I | List - II |
a) ![]() | i) ![]() |
b) ![]() | ii) ![]() |
c) ![]() | iii) ![]() |
d) ![]() | iv) ![]() |
Codes :
\(\dfrac{d^{2}y}{dt^{2}}+y=0\) can be solved using an Operational Amplifier. Which one is preferred ?
In the circuit shown below, $R$ is $1\text{ k}\Omega$ and $R_f$ is $10\text{ k}\Omega$. If $V_{\text{in}}$ is $100\text{ mV}$ and the op-amps have supply voltages of $\pm 15\text{ V}$, then $V_{\text{out}}$ is _______ V.

For IC 741 circuit shown below, the maximum input frequency above which the output will be distorted is ____________.

Assume that an op-amp 741 connected as a unit gain inverting amplifier is applied with an input change of 10 V. Determine the time taken for the output to change by 10 V. [Slew rate for op-amp 741 = 0.5 V/µs]
What is the value of output voltage $V_o$ in the given circuit? Assume op-amp to be ideal and MOSFET operating in saturation region.
In an ideal op-amp, the common mode gain is _____________.