Match the following : Codes :List – I List – II a. LASER i. Emits monochromatic light of low intensity b. Solar cell ii. Consumes electrical power due to tHe incident light c. Photo diode iii. Delivers power to load d. LED iv. Emits monochromatic light of high intensity
a-iv, b-iii, c-ii, d-i
The four devices split into two emitters and two detectors, and within each pair one clear property separates them — giving a-iv, b-iii, c-ii, d-i, option 3.
| Device | Direction | Distinguishing feature |
|---|---|---|
| a. LASER | Emitter | iv. High intensity, monochromatic |
| d. LED | Emitter | i. Low intensity |
| b. Solar cell | Detector | iii. Delivers power |
| c. Photodiode | Detector | ii. Consumes power |
LASER against LED — the emitters. Both work by recombination in a forward-biased junction, but the LED emits spontaneously: each photon is released independently, in a random direction and with a random phase, giving a broad spectrum some tens of nanometres wide and a diffuse beam. The laser adds an optical cavity and enough pumping to reach population inversion, so emission becomes stimulated — each photon triggers another identical to it in phase and direction. The result is coherent, far narrower in linewidth, and enormously brighter for the same junction area.
Solar cell against photodiode — the detectors. Physically they are the same p-n junction; the difference is the quadrant of the I-V characteristic in which they are operated.
The solar cell works with no external bias, in the fourth quadrant where the voltage is positive and the current negative. The product \(VI\) is therefore negative — the junction is a source, and it delivers power to the load. That is its whole purpose, characterised by
\(P_{max}=V_{oc}I_{sc}\times FF\)
The photodiode is reverse biased, in the third quadrant, so voltage and current have the same sign and the device consumes power from the supply. Nothing is gained in energy — what is gained is speed and linearity: the reverse bias widens the depletion region, reduces the junction capacitance, and makes the photocurrent very accurately proportional to the incident light.
The pairing of purposes is neat: energy conversion wants the unbiased mode, and measurement wants the biased one.
Hence, the correct code is a-iv, b-iii, c-ii, d-i.
Which one of the following is not LED material ?
1. Ga As
2. Ga P
3. Si
4. SiO2
When atoms in Direct bandgap semiconductors move from higher energy state (E2) to lower energy state (E1) and emission of light takes place, the energy of emitted photon is given as
Match the following :
| List – I | List – II |
| a. LED | i. Heavily doped |
| b. Avalanche Photodiode | ii. Coherent radiation |
| c. Tunnel diode | iii. Spontaneous emission |
| d. LASER | iv. Current gain |
Codes :
Match List I with List II
| LIST I | LIST II | ||
|---|---|---|---|
| A. | LED | I. | Photo resistive effect |
| B. | LCD | II. | Photo conductive effect |
| C. | LDR | III. | dynamic scattering of light |
| D. | Photo Diode | IV. | electro - luminescence |
Choose the correct answer from the options given below:
Match the following lists :
| List - I | List - II |
a) ![]() | i) Solar cell |
b) ![]() | ii) Pn-photodiode |
c) ![]() | iii) Pin photodiode |
d) ![]() | iv) Light emitting diode |
Choose the correct answer from the codes given below:
Which of the following statements are correct in case of Light Emitting Diodes ?
(a) Homojunctions LEDs are often surface emitters.
(b) Heterojunctions LEDs are Edge emitters.
(c) Heterojunction LEDs are often surface emitters.
(d) LEDs provide monochromatic & coherent radiations.
Options :
Arrange the below mentioned III-V materials to produce LEDs in order of their increasing emission wavelengths :
(a) In AS (b) Si C (c) Ga P (d) Ga AS
Codes :
The material LiNbO3 is used in the manufacturing of the following device :
Light emitting diodes fabricated from Ga, As emit radiations in the :
Which computer application scans texts and converts into readable form in computer?
Light wave propagation is possible in optical fibre due to a phenomenon called:
An LCD requires a power of __________.