Consider the following statements : (A) The output voltage of a summing amplifier (inverting configuration) with three inputs VA, VB and VC and input resistors RA, RB and RC is \(V_{o}=\left(1+\dfrac{R_{F}}{R_{A}R_{B}R_{C}}\right)\left[\dfrac{V_{A}}{R_{A}}+\dfrac{V_{B}}{R_{B}}+\dfrac{V_{C}}{R_{C}}\right]\) Choose the most appropriate answer from the options given below :
(B) In a subtractor circuit, the output voltage is equal to voltage applied to non-inverting terminal minus voltage applied to inverting terminal
(C) The narrow band pass filter is called a Notch filter
(D) VCO is also called as frequency to voltage
(E) The all pass filter provides unity-gain with predictable phase shifts for different input frequencies
(B) and (E) Only
Only (B) and (E) survive — option 4 — and the other three each invert or garble a standard result.
(A) is wrong on two counts. The inverting summer's output is
\(V_{o}=-R_{F}\left(\dfrac{V_{A}}{R_{A}}+\dfrac{V_{B}}{R_{B}}+\dfrac{V_{C}}{R_{C}}\right)\)
First, an inverting configuration must produce a minus sign, and the statement has none. Second, its factor \(\left(1+R_{F}/R_{A}R_{B}R_{C}\right)\) is dimensionally impossible — adding 1 to a resistance divided by the product of three resistances gives units of reciprocal ohms squared. The correct expression simply multiplies the sum of input currents by \(R_{F}\), since all three currents meet at the virtual earth.
(B) is correct. The difference amplifier with matched resistors gives
\(V_{o}=\dfrac{R_{F}}{R_{1}}\left(V_{+}-V_{-}\right)\)
and with unity gain that is exactly the non-inverting input minus the inverting input, as stated.
(C) confuses two opposite filters. A notch filter is a narrow band-reject filter: it removes a narrow band and passes everything else, which is how mains hum at 50 Hz is eliminated. A narrow band-pass filter does the reverse. The two have complementary responses, so calling one by the other's name is a clear error.
(D) is backwards. VCO stands for voltage-controlled oscillator — a voltage in, a frequency out, so it is a voltage-to-frequency converter. The frequency-to-voltage converter is the opposite device, as Q13 of this paper describes.
(E) is correct, and describes exactly what an all-pass filter is for. Its magnitude response is flat at unity for every frequency:
\(H(s)=\dfrac{s-a}{s+a},\qquad \left|H(j\omega)\right|=1\)
while its phase varies from 0° to −180°. Since it changes nothing about amplitude, its whole purpose is phase — delay equalisation in transmission lines, phase shifters in SSB modulators, and correcting the group delay of other filters.
Hence, the correct statements are (B) and (E).
Assertion (A) : An Op-Amp is a direct coupled high gain amplifier.
Reason (R) : It consists of one or more differential amplifiers and usually followed by a level translator and push pull stage.
The input to a differentiator is –5 V. Its output will be
Match the following :
| List – I | List – II |
| a. h-parameters | i. O/P voltage varies as the slope of i/p voltage |
| b. differentiator | ii. Noise division |
| c. half-wave rectifier | iii. Function of a Q point |
| d. integrator | iv. series diode clipper |
Codes :
Assertion (A) : Op-Amp is used for sensor circuit.
Reason (R) : A small signal amplifier amplify weak measured signals.
For an inverting comparator circuit acting as a Schmitt Trigger, as shown in figure below, the expression of Hysteresis Voltage (Vny) is given by :

Consider the following circuit, the switch S1 allows the output to switch between two ranges of amplitudes from 0-0.1 V and 0-1 V. Arrange these values of R1, R2 and R3 in increasing order.

(A) Value of R1
(B) Value of R2
(C) Value of R3
Choose the most appropriate answer from the options given below :
Match List I with List II
| LIST I | LIST II | ||
|---|---|---|---|
| A. | Butterworth filter of order '2' | I. | Impedance matching |
| B. | Buffer | II. | CMRR = ∞ (infinity) |
| C. | Schmitt Trigger | III. | Positive feedback |
| D. | Ideal OPAMP | IV. | 40 dB/decade roll off |
Choose the correct answer from the options given below:
The given operational amplifier circuit corresponds to which electronic circuit application ?

Statements in connection to Op-Amp applications are :
A. If we use a square wave generator followed by integrator circuit we get a triangular wave at the output
B. The logarithmic amplifier called a log-amplifier or a logger, is basically a current to voltage converter.
C.
is a first order high pass filter with voltage follower
D. If we use a square wave generator followed by a clipping circuit then we get a saw-tooth wave generator.
Choose the correct answer from the options given below:
Match List I with List II
| LIST I | LIST II | ||
|---|---|---|---|
| A. | Single polarity positive voltage clipper circuit | I. | ![]() |
| B. | Negative clamping circuit | II. | ![]() |
| C. | Differentiator circuit | III. | ![]() |
| D. | Logarithmic Amplifier | IV. | ![]() |
Choose the correct answer from the options given below:
What is the typical value of open-loop voltage gain, AVOL, for a 741 op-amp?
An ideal Op-Amp is an ideal
Which of the following statements about the Op-Amp differential amplifiers is INCORRECT?
The total output offset voltage of an operational amplifier is a function of these effects.