A worker completes \(\frac{3}{5}\) of a work in 12 days. In how many days will he complete \(\frac{3}{4}\) of the work?
15
The question describes a scenario where a worker completes a certain fraction of a task in a given number of days. We need to find out how many days it will take the same worker to complete a different fraction of the same task, assuming their work rate remains constant.
Problems involving work and time often rely on the concept of the rate of work, which is the amount of work done per unit of time.
We are told that the worker completes \(\frac{3}{5}\) of the total work in 12 days.
The rate of work can be calculated as:
Rate = \(\frac{\text{Amount of Work Done}}{\text{Time Taken}}\)
In this case, the amount of work done is \(\frac{3}{5}\) and the time taken is 12 days.
Rate = \(\frac{\frac{3}{5}}{12}\) work per day
To simplify this fraction, we can write it as multiplication:
Rate = \(\frac{3}{5} \times \frac{1}{12}\) work per day
Rate = \(\frac{3 \times 1}{5 \times 12}\) work per day
Rate = \(\frac{3}{60}\) work per day
This fraction can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 3.
Rate = \(\frac{3 \div 3}{60 \div 3}\) work per day
Rate = \(\frac{1}{20}\) work per day
So, the worker completes \(\frac{1}{20}\) of the total work every day.
Now we want to find out how many days it will take the worker to complete \(\frac{3}{4}\) of the work at the rate of \(\frac{1}{20}\) work per day.
The relationship between time, work, and rate is:
Time = \(\frac{\text{Amount of Work to be Done}}{\text{Rate of Work per Day}}\)
Here, the amount of work to be done is \(\frac{3}{4}\) and the rate is \(\frac{1}{20}\) work per day.
Time = \(\frac{\frac{3}{4}}{\frac{1}{20}}\) days
To divide by a fraction, we multiply by its reciprocal:
Time = \(\frac{3}{4} \times \frac{20}{1}\) days
Time = \(\frac{3 \times 20}{4 \times 1}\) days
Time = \(\frac{60}{4}\) days
Now, we perform the division:
Time = 15 days
Therefore, the worker will complete \(\frac{3}{4}\) of the work in 15 days.
The worker will complete \(\frac{3}{4}\) of the work in 15 days.
| Concept | Explanation | How it's used here |
|---|---|---|
| Work Done | The portion of the total task completed. Represented as a fraction or percentage. | Given as \(\frac{3}{5}\) and \(\frac{3}{4}\) of the total work. |
| Time Taken | The duration required to complete a specific amount of work. | Given as 12 days; we need to find another time. |
| Rate of Work | The amount of work completed per unit of time (e.g., per day, per hour). Assumed constant unless stated otherwise. | Calculated as \(\frac{1}{20}\) of the work completed per day. |
| Relationship | Work Done = Rate \(\times\) Time Taken. Time Taken = \(\frac{\text{Work Done}}{\text{Rate}}\). Rate = \(\frac{\text{Work Done}}{\text{Time Taken}}\). | Used to calculate the rate from the initial information and then calculate the required time. |
Work and Time problems with a constant rate can also be solved using proportionality. If a worker completes \(W_1\) amount of work in \(T_1\) time, and \(W_2\) amount of work in \(T_2\) time, assuming a constant rate, the ratio of work to time is constant:
\(\frac{W_1}{T_1} = \frac{W_2}{T_2}\)
In this problem:
Setting up the proportion:
\(\frac{3/5}{12} = \frac{3/4}{T_2}\)
This simplifies to:
\(\frac{3}{5 \times 12} = \frac{3}{4 \times T_2}\)
\(\frac{3}{60} = \frac{3}{4 \times T_2}\)
Simplifying the left side:
\(\frac{1}{20} = \frac{3}{4 \times T_2}\)
Cross-multiply:
\(1 \times (4 \times T_2) = 3 \times 20\)
\(4 \times T_2 = 60\)
Divide by 4:
\(T_2 = \frac{60}{4}\)
\(T_2 = 15\)
This confirms that it takes 15 days to complete \(\frac{3}{4}\) of the work.
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