4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 25 women complete it?
16
This question is a classic example of a work and time problem, often found in quantitative aptitude sections of exams. It involves calculating the efficiency of individuals (men and women in this case) and then using that to find the time taken by a different group to complete the same work.
Let's define the work rate of one man and one woman per day:
The total work done is the product of the number of workers, their individual work rate, and the number of days they work.
According to the problem, we have two scenarios:
Scenario 1:
4 men and 6 women can complete the work in 8 days.
Work done by 4 men in one day = \(4m\)
Work done by 6 women in one day = \(6w\)
Total work done by the group in one day = \(4m + 6w\)
Total work done in 8 days = \(8 \times (4m + 6w)\)
Total work = \(32m + 48w\) (Equation 1)
Scenario 2:
3 men and 7 women can complete the work in 10 days.
Work done by 3 men in one day = \(3m\)
Work done by 7 women in one day = \(7w\)
Total work done by the group in one day = \(3m + 7w\)
Total work done in 10 days = \(10 \times (3m + 7w)\)
Total work = \(30m + 70w\) (Equation 2)
Since the total work completed is the same in both scenarios, we can equate Equation 1 and Equation 2:
\(32m + 48w = 30m + 70w\)
Now, we solve for the relationship between \(m\) and \(w\). Let's bring all terms with \(m\) to one side and all terms with \(w\) to the other side:
\(32m - 30m = 70w - 48w\)
\(2m = 22w\)
Dividing both sides by 2:
\(m = 11w\)
This result tells us that the amount of work done by one man in a day is equal to the amount of work done by 11 women in a day. In other words, one man is as efficient as 11 women.
Now that we know the relationship between \(m\) and \(w\), we can express the total work in terms of \(w\) using either Equation 1 or Equation 2. Let's use Equation 1:
Total work = \(32m + 48w\)
Substitute \(m = 11w\) into this equation:
Total work = \(32(11w) + 48w\)
Total work = \(352w + 48w\)
Total work = \(400w\)
This means the total work required is equivalent to the work done by 400 women working for one day (or 400 woman-days of work).
We need to find out how many days it will take for 25 women to complete this total work (\(400w\)).
Work done by 25 women in one day = \(25w\)
Let \(D\) be the number of days required for 25 women to complete the work.
Total work = (Work done by 25 women in one day) \(\times\) (Number of days)
\(400w = 25w \times D\)
To find \(D\), divide the total work by the work done by 25 women in one day:
\(D = \frac{400w}{25w}\)
The \(w\) terms cancel out:
\(D = \frac{400}{25}\)
Now, perform the division:
\(D = 16\)
So, 25 women will complete the work in 16 days.
| Group | Days | Total Work Expression |
|---|---|---|
| 4 Men + 6 Women | 8 | \(8(4m + 6w) = 32m + 48w\) |
| 3 Men + 7 Women | 10 | \(10(3m + 7w) = 30m + 70w\) |
| Equating Work: | \(32m + 48w = 30m + 70w\) | |
| Result: | \(m = 11w\) | |
| Total Work (in terms of w): | \(32(11w) + 48w = 400w\) | |
| Time for 25 Women: | ? | \(\frac{400w}{25w} = 16\) days |
25 women will complete the work in 16 days.
| Concept | Explanation |
|---|---|
| Work Rate | The amount of work done by a person or group per unit of time (e.g., per day). |
| Total Work | The total amount of task to be completed. It is often represented as a single unit or measured in terms of person-days (or woman-days, man-days). |
| Relationship Formula | Total Work = Work Rate \(\times\) Time. This fundamental formula is used to solve most work and time problems. |
| Efficiency | Often relates to the work rate. A more efficient worker has a higher work rate. If \(m = 11w\), a man is 11 times more efficient than a woman. |
Problems involving different groups of people working together can be solved by first finding the individual work rates. Here are some tips:
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