The bisector of ∠B in ΔABC meets AC at D. If AB = 12 cm, BC = 18 cm and AC = 15 cm, then the length of AD (in cm) is:
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This problem asks us to find the length of a segment on one side of a triangle created by an angle bisector from the opposite vertex. We are given the lengths of all three sides of triangle ABC, and we know that BD is the bisector of angle B, meeting side AC at point D.
To solve this problem, we need to use a fundamental concept in geometry known as the Angle Bisector Theorem. This theorem provides a relationship between the lengths of the sides of a triangle and the segments created by an angle bisector on the opposite side.
The Angle Bisector Theorem states that in a triangle, the angle bisector of any angle divides the opposite side in the ratio of the lengths of the other two sides. For ΔABC, where BD is the angle bisector of ∠B meeting AC at D, the theorem says:
$\frac{AD}{DC} = \frac{AB}{BC}$
We are given the following lengths:
According to the Angle Bisector Theorem, we have:
$\frac{AD}{DC} = \frac{AB}{BC}$
Substitute the given values for AB and BC:
$\frac{AD}{DC} = \frac{12}{18}$
Simplify the fraction $\frac{12}{18}$:
$\frac{12}{18} = \frac{6 \times 2}{6 \times 3} = \frac{2}{3}$
So, the ratio $\frac{AD}{DC} = \frac{2}{3}$. This means that the segment AD and the segment DC are in the ratio 2 : 3. The side AC is divided into two segments, AD and DC, and their sum is equal to the length of AC.
AD + DC = AC
AD + DC = 15 cm
Since AD : DC = 2 : 3, we can consider AC as being divided into $2 + 3 = 5$ parts. The length of AD corresponds to 2 of these parts, and the length of DC corresponds to 3 of these parts.
To find the length of AD, we can use the ratio in relation to the total length of AC:
$AD = \left(\frac{\text{Ratio part for AD}}{\text{Total ratio parts}}\right) \times AC$
$AD = \left(\frac{2}{2 + 3}\right) \times 15$
$AD = \left(\frac{2}{5}\right) \times 15$
Now, calculate the value:
$AD = \frac{2 \times 15}{5}$
$AD = \frac{30}{5}$
$AD = 6$
Therefore, the length of AD is 6 cm.
We can also find the length of DC to verify: $DC = \left(\frac{\text{Ratio part for DC}}{\text{Total ratio parts}}\right) \times AC$ $DC = \left(\frac{3}{2 + 3}\right) \times 15$ $DC = \left(\frac{3}{5}\right) \times 15$ $DC = \frac{3 \times 15}{5} = \frac{45}{5} = 9$ cm.
Check: AD + DC = 6 cm + 9 cm = 15 cm, which is indeed the length of AC.
| Given Information | Calculation Step | Result |
|---|---|---|
| AB = 12 cm, BC = 18 cm | Ratio $\frac{AD}{DC} = \frac{AB}{BC}$ | $\frac{AD}{DC} = \frac{12}{18} = \frac{2}{3}$ |
| AC = 15 cm, AD : DC = 2 : 3 | Total ratio parts = 2 + 3 | Total ratio parts = 5 |
| AC = 15 cm, Total ratio parts = 5 | Length of AD = $\frac{2}{5} \times AC$ | AD = $\frac{2}{5} \times 15 = 6$ cm |
| AC = 15 cm, Total ratio parts = 5 | Length of DC = $\frac{3}{5} \times AC$ | DC = $\frac{3}{5} \times 15 = 9$ cm |
| AD = 6 cm, DC = 9 cm | Check AD + DC | 6 + 9 = 15 cm (Matches AC) |
Using the Angle Bisector Theorem and the given side lengths of triangle ABC, we found that the bisector of angle B divides the side AC into segments AD and DC in the ratio 2:3. By dividing the total length of AC (15 cm) according to this ratio, we determined the length of segment AD.
The length of AD is 6 cm.
| Concept | Description | Formula (for ΔABC, BD bisects ∠B) |
|---|---|---|
| Angle Bisector | A line segment that divides an angle into two equal angles. | BD is the angle bisector of ∠B |
| Angle Bisector Theorem | A theorem relating the ratio of sides to the ratio of segments formed by an angle bisector on the opposite side. | $\frac{AD}{DC} = \frac{AB}{BC}$ |
| Segment Division | The opposite side is divided into two segments proportional to the adjacent sides. | AD and DC are segments of AC |
Understanding the Angle Bisector Theorem is crucial for solving various geometry problems involving triangles. Here are some related concepts:
Mastering these concepts helps build a strong foundation in geometry.
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