ABCD is a trapezium in which AB is parallel to DC. Let E and F be the midpoints on AD and BC respectively. If EF = 10 cm and AB - DC = 4 cm, then what is the value of AB × DC?
Let's break down this geometry problem involving a trapezium and its midpoints. We are given a trapezium ABCD where side AB is parallel to side DC. E and F are the midpoints of the non-parallel sides AD and BC, respectively.
We are provided with two key pieces of information:
Our goal is to find the value of the product of the lengths of the parallel sides, i.e., AB × DC.
A crucial property of a trapezium states that the line segment connecting the midpoints of the non-parallel sides is parallel to the parallel sides and its length is equal to half the sum of the lengths of the parallel sides. Mathematically, this can be written as:
\(EF = \frac{1}{2}(AB + DC)\)
We can substitute the given length of EF into this formula:
\(10 = \frac{1}{2}(AB + DC)\)
Multiplying both sides by 2, we get:
\(20 = AB + DC \quad \text{(Equation 1)}\)
We are also given the difference between the lengths of the parallel sides:
\(AB - DC = 4 \quad \text{(Equation 2)}\)
Now we have a system of two linear equations with two variables, AB and DC:
| Equation | Form |
|---|---|
| Equation 1 | \(AB + DC = 20\) |
| Equation 2 | \(AB - DC = 4\) |
We can solve this system by adding the two equations. Adding Equation 1 and Equation 2 eliminates DC:
\((AB + DC) + (AB - DC) = 20 + 4\)
\(AB + AB + DC - DC = 24\)
\(2AB = 24\)
Dividing both sides by 2:
\(AB = \frac{24}{2}\)
\(AB = 12 \text{ cm}\)
Now substitute the value of AB (12 cm) into either Equation 1 or Equation 2 to find DC. Using Equation 1:
\(12 + DC = 20\)
Subtract 12 from both sides:
\(DC = 20 - 12\)
\(DC = 8 \text{ cm}\)
We have found the lengths of the parallel sides:
We need to find the value of AB × DC:
\(AB \times DC = 12 \times 8\)
\(AB \times DC = 96\)
The value of AB × DC is 96. The unit provided in the options is square cm, which typically denotes area, but here it represents the numerical product of the lengths.
| Concept | Description |
|---|---|
| Trapezium (Trapezoid) | A quadrilateral with at least one pair of parallel sides. The parallel sides are called bases. |
| Bases | The parallel sides of a trapezium (e.g., AB and DC in this problem). |
| Non-parallel sides | The other two sides of the trapezium (e.g., AD and BC). |
| Midpoint Segment (Median) | The line segment connecting the midpoints of the non-parallel sides. Its length is half the sum of the bases. |
Beyond the midpoint segment property, trapeziums have other interesting characteristics:
The area of a sector of a circle of radius 4 cm is 25.6 cm 2. What is the radian measure of the arc of the sector?
If the perimeter of a right-angled triangle is 30 cm and the hypotenuse is 13 cm, then what is the area of the triangle?
The lengths of the sides of a right-angled triangle are consecutive even integers (in cm). What is the product of these integers?
The arch of a bridge is in the form of an arc of a circle. If the span of the bridge is 40 m and height in the middle is 8 m, then what is the radius of curvature of the bridge?
Let x be the area of a square inscribed in a circle of radius r and y be the area of an equilateral triangle inscribed in the same circle. Which one of the following is correct ?
If the length of a rectangle is increased by \(66 \frac{2}{3} \%\), then by what percent should the width of the rectangle be decreased in order to maintain the same area ?
The perimeter and the area of a right-angled triangle are 36 cm and 54 square cm respectively. What is the length of the hypotenuse?
What is the ratio of the area of the circle to the area of the rectangle ?
What is the area of Δ AEC ?
What is the area of a triangle with sides of length 12 cm, 13 cm and 5 cm?
If the area of a square is 625 cm 2, then what is the perimeter of the square?
The area and the perimeter of a sheet of paper are 240 cm 2and 68 cm, respectively. What would be its length and breadth?
One side of rectangular field is 15 meters and one of its diagonals is 17 meters. Then find the area of the field.
The bisector of ∠B in ΔABC meets AC at D. If AB = 12 cm, BC = 18 cm and AC = 15 cm, then the length of AD (in cm) is:
The perimeter and the length of one of the diagonals of a rhombus is 26 cm and 5 cm respectively. Find the length of its other diagonal (in cm).