20 women and 15 men together can complete a work in 6 days. It takes 150 days for a single woman to complete the work. In how many days can a single man complete the work?
450
This problem involves understanding the concept of work rate and how it applies to multiple individuals working together. We are given information about the time it takes for individuals and groups to complete a certain amount of work, and we need to find the time it takes for a single man to complete the same work.
Work rate is the amount of work done by a person or group in a unit of time, usually one day. If a person takes $D$ days to complete a work, their daily work rate is $\frac{1}{D}$ of the total work.
We are given the following information:
Let's define the work rates:
From the first piece of information:
The daily work rate of a single woman ($W$) is $\frac{1}{150}$ of the work per day.
So, $W = \frac{1}{150}$.
Now, consider the group working together:
When they work together, their total combined daily work rate is the sum of their individual combined rates:
Total combined daily work rate = $20W + 15M$
We know that this group completes the work in 6 days. This means their total combined daily work rate is $\frac{1}{6}$ of the total work per day.
So, we can set up the equation:
$20W + 15M = \frac{1}{6}$
Now, substitute the value of $W$ into the equation:
$20 \left(\frac{1}{150}\right) + 15M = \frac{1}{6}$
Simplify the term for women's work:
$\frac{20}{150} + 15M = \frac{1}{6}$
Reduce the fraction $\frac{20}{150}$:
$\frac{20}{150} = \frac{2}{15}$
The equation becomes:
$\frac{2}{15} + 15M = \frac{1}{6}$
To find $15M$, subtract $\frac{2}{15}$ from both sides of the equation:
$15M = \frac{1}{6} - \frac{2}{15}$
To subtract the fractions on the right side, find a common denominator for 6 and 15. The least common multiple (LCM) of 6 and 15 is 30.
Now perform the subtraction:
$15M = \frac{5}{30} - \frac{4}{30}$
$15M = \frac{1}{30}$
To find $M$ (the daily work rate of a single man), divide both sides by 15:
$M = \frac{1}{30 \times 15}$
$M = \frac{1}{450}$
The daily work rate of a single man is $M = \frac{1}{450}$. This means a single man completes $\frac{1}{450}$ of the total work in one day.
The time taken for a single man to complete the entire work is the reciprocal of his daily work rate:
Time Taken for Single Man = $\frac{1}{M} = \frac{1}{1/450} = 450$ days.
Therefore, a single man can complete the work in 450 days.
The calculation shows that a single man takes 450 days to complete the work.
| Worker Type | Time Taken (Days) | Daily Work Rate |
|---|---|---|
| Single Woman | 150 | $\frac{1}{150}$ |
| Single Man | ? | $M = \frac{1}{450}$ |
| 20 Women & 15 Men | 6 | $\frac{1}{6}$ |
Understanding the relationship between work, rate, and time is key to solving these types of problems.
| Concept | Formula | Explanation |
|---|---|---|
| Work Rate | Rate = Work / Time | Amount of work done per unit of time. Often expressed as a fraction of total work per day. |
| Total Work | Work = Rate $\times$ Time | The total amount of work to be completed (often normalized to 1). |
| Combined Rate | Rate$_{total}$ = Rate$_1$ + Rate$_2$ + ... | When multiple people work together, their individual rates are added to find the total combined rate. |
| Time Taken | Time = Work / Rate | The time needed to complete a certain amount of work at a given rate. If work is 1, Time = 1 / Rate. |
Work and time problems often involve multiple people or machines working at different rates. Here are some common strategies:
These problems are a common application of inverse proportionality, as rate and time are inversely proportional (higher rate means less time to complete the same work).
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