A man completes 7/8 of a job in 21 days. How many more days will it take him to finish the job if quantum of work further increased by 50%?
15
Given;
Time taken to complete 7/8 of a job = 21 days
Quantum of work further increased by 50%
Calculation:
Time required to complete the job = \(\frac {21}{7/8} \) = 24 days
So time taken by the man to complete 50% work, t 1= 24/2 = 12 days
Also, remaining work after 21 days = 1 - 7/8 = 1/8 and
time required to complete 1/8 of the job, t 2= Time required to complete whole work - time taken to complete 7/8 of the job i.e.
= 24 - 21 = 3 days
Now the number of days required = t 1 + t 2
= 12 + 3 = 15days
Hence, option 4 is correct.
Important Questions from Work Efficiency
24 men and 12 women can do a piece of work in 30 days. In how many days can 12 men and 24 women do the same piece of work?
A and B together can do a piece of work in 4 days, B and C can do it in 6 days, A and C can do it in 8 days. Then A, B and C together can do the same work in :-
A can complete 50% of a work in 9 days and B can do 25% of the work in 9 days, if they work alone. If they work together then how much work (in percentage) can be completed in 6 days?
A is thrice as good a workman as B. C alone takes 48 days to paint a house. All three A, B and C working together take 16 days to paint the house. It will take how many days for A alone to paint the house?
A can do a piece of work in 12 days. B can do that work in 36 days. After working together for 3 days, B left the job. In how many days can A complete the remaining work?
