This solution explains the calculation of compound interest compounded half-yearly.
We need to find the compound interest on a principal amount for a given time period and interest rate, compounded half-yearly.
Since the interest is compounded half-yearly, we adjust the rate and time:
The formula for the amount (A) when compounded is:
$ A = P \left(1 + r\right)^n $Substitute the values:
$ A = 2800 \left(1 + 0.05\right)^3 $ $ A = 2800 \left(1.05\right)^3 $ $ A = 2800 \times 1.157625 $ $ A = 3241.35 $So, the total amount after $1\frac{1}{2}$ years is ₹3,241.35.
The compound interest (CI) is the difference between the final amount and the principal amount:
$ \text{CI} = A - P $ $ \text{CI} = 3241.35 - 2800 $ $ \text{CI} = 441.35 $The compound interest is ₹441.35.
Find the interest (in ₹) on ₹8,000 at 10% per annum compounded half yearly for $1\frac{1}{2}$ years.
The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. The rate of interest per annum is?
A sum of Rs. 2000 amounts to Rs. 4000 in two years at compound interest. In how many years does the same amount becomes Rs. 8000?
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, the compound interest on the same at the same rate and for the same time is: