If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, the compound interest on the same at the same rate and for the same time is:
51.25
This question asks us to first find the principal amount using the given simple interest details and then calculate the compound interest on that same principal for the same rate and time period. Let's break it down step by step.
We are given the simple interest (SI), the rate of interest (R), and the time period (T). The formula for simple interest is:
\(SI = \frac{P \times R \times T}{100}\)
Where:
Let's plug the given values into the formula:
\(50 = \frac{P \times 5 \times 2}{100}\)
Simplify the equation:
\(50 = \frac{10P}{100}\)
\(50 = \frac{P}{10}\)
Now, solve for P:
\(P = 50 \times 10\)
\(P = 500\)
So, the principal amount is Rs. 500.
Now we need to find the compound interest (CI) on the principal amount (P = Rs. 500) at the same rate (R = 5%) for the same time period (T = 2 years).
The formula for the amount (A) with compound interest is:
\(A = P \left(1 + \frac{R}{100}\right)^T\)
Plug in the values:
\(A = 500 \left(1 + \frac{5}{100}\right)^2\)
\(A = 500 \left(1 + \frac{1}{20}\right)^2\)
\(A = 500 \left(\frac{20+1}{20}\right)^2\)
\(A = 500 \left(\frac{21}{20}\right)^2\)
\(A = 500 \times \frac{21^2}{20^2}\)
\(A = 500 \times \frac{441}{400}\)
We can simplify this by cancelling common factors:
\(A = \frac{500 \times 441}{400}\)
\(A = \frac{5 \times 441}{4}\)
\(A = \frac{2205}{4}\)
\(A = 551.25\)
The amount after 2 years with compound interest is Rs. 551.25.
To find the compound interest (CI), we subtract the principal amount from the total amount:
\(CI = A - P\)
\(CI = 551.25 - 500\)
\(CI = 51.25\)
The compound interest is Rs. 51.25.
Let's compare our calculated compound interest with the given options:
Our calculated value of Rs. 51.25 matches Option 2.
Based on the calculations, the compound interest on the sum of money (Rs. 500) for 2 years at 5% per annum is Rs. 51.25. This confirms that Option 2 is the correct answer.
| Concept | Formula | Calculation for this Problem |
|---|---|---|
| Simple Interest (SI) | \(SI = \frac{P \times R \times T}{100}\) | \(50 = \frac{P \times 5 \times 2}{100} \Rightarrow P = 500\) |
| Amount with Compound Interest (A) | \(A = P \left(1 + \frac{R}{100}\right)^T\) | \(A = 500 \left(1 + \frac{5}{100}\right)^2 = 551.25\) |
| Compound Interest (CI) | \(CI = A - P\) | \(CI = 551.25 - 500 = 51.25\) |
Understanding the difference between simple interest and compound interest is crucial.
In this problem, the simple interest for 2 years is Rs. 50, meaning Rs. 25 is earned each year (\(50/2\)). With compound interest, the interest from the first year (Rs. 25) is added to the principal for the second year's calculation. So, in the second year, interest is earned on Rs. 500 + Rs. 25 = Rs. 525.
Let's see the difference year-by-year:
This step-by-step breakdown shows why the compound interest (Rs. 51.25) is slightly more than the simple interest (Rs. 50) over 2 years.
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