This problem involves finding the initial amount of money (the principal) invested based on the difference between the compound interest earned and the simple interest earned over a period of three years.
The specific formula relating the difference between Compound Interest (CI) and Simple Interest (SI) for 3 years is:
Difference = $P \times (\frac{R}{100})^2 \times (3 + \frac{R}{100})$
Where:
We are given:
Substitute the known values into the formula:
₹217 = $P \times (\frac{10}{100})^2 \times (3 + \frac{10}{100})$
₹217 = $P \times (\frac{1}{10})^2 \times (3 + \frac{1}{10})$
₹217 = $P \times (\frac{1}{100}) \times (\frac{30}{10} + \frac{1}{10})$
₹217 = $P \times (\frac{1}{100}) \times (\frac{31}{10})$
₹217 = $P \times \frac{31}{1000}$
$P = ₹217 \times \frac{1000}{31}$
$P = ₹7 \times 1000$
$P = ₹7,000$
Therefore, the principal amount is ₹7,000. This amount, when subjected to a 10% annual interest rate for three years, results in a difference of ₹217 between the compound interest and simple interest earned.
Amit had invested same amount of sums at simple as well as compound interest, compounded annually. The time period of investment for both the sums was 2 years and rate of interest too was the same, 4% per annum. At the end, he found a difference of ₹43 in both the interests received. What were the sums (in ₹) invested?
When the difference between compound interest, compounded annually, and simple interest for three years is ₹186 at 10% interest per annum, the principal is ₹______.