This problem involves finding the initial amount of money (the principal) invested based on the difference between the compound interest earned and the simple interest earned over a period of three years.
The specific formula relating the difference between Compound Interest (CI) and Simple Interest (SI) for 3 years is:
Difference = $P \times (\frac{R}{100})^2 \times (3 + \frac{R}{100})$
Where:
We are given:
Substitute the known values into the formula:
₹217 = $P \times (\frac{10}{100})^2 \times (3 + \frac{10}{100})$
₹217 = $P \times (\frac{1}{10})^2 \times (3 + \frac{1}{10})$
₹217 = $P \times (\frac{1}{100}) \times (\frac{30}{10} + \frac{1}{10})$
₹217 = $P \times (\frac{1}{100}) \times (\frac{31}{10})$
₹217 = $P \times \frac{31}{1000}$
$P = ₹217 \times \frac{1000}{31}$
$P = ₹7 \times 1000$
$P = ₹7,000$
Therefore, the principal amount is ₹7,000. This amount, when subjected to a 10% annual interest rate for three years, results in a difference of ₹217 between the compound interest and simple interest earned.
The difference between the simple interest and the compound interest, compounded annually, on a certain sum of money for 2 years at 17% per annum is ₹967. Find the sum [rounded off to the nearest integer].
When the difference between compound interest, compounded annually, and simple interest for three years is ₹186 at 10% interest per annum, the principal is ₹______.