Person A deposited ₹8,000 at 8% simple interest for 3 years. The formula for simple interest (SI) is:
$ SI = \frac{P \times R \times T}{100} $
Where:
Substituting the values:
$ SI_A = \frac{8000 \times 8 \times 3}{100} $
$ SI_A = 80 \times 8 \times 3 $
$ SI_A = 640 \times 3 $
$ SI_A = ₹1,920 $
Person B deposited ₹6,000 at 10% compound interest per annum for 3 years. The formula for the amount (A) after compound interest is:
$ A = P \left(1 + \frac{R}{100}\right)^T $
Where:
First, calculate the total amount (A) after 3 years:
$ A_B = 6000 \left(1 + \frac{10}{100}\right)^3 $
$ A_B = 6000 \left(1 + 0.1\right)^3 $
$ A_B = 6000 \left(1.1\right)^3 $
$ A_B = 6000 \times 1.331 $
$ A_B = ₹7,986 $
The compound interest (CI) earned is the total amount minus the principal:
$ CI_B = A_B - P $
$ CI_B = 7986 - 6000 $
$ CI_B = ₹1,986 $
The difference between their interests is the absolute difference between the compound interest earned by B and the simple interest earned by A.
Difference = $ CI_B - SI_A $
Difference = $ ₹1,986 - ₹1,920 $
Difference = $ ₹66 $
The difference between their interests after 3 years is ₹66.
Find the interest (in ₹) on ₹8,000 at 10% per annum compounded half yearly for $1\frac{1}{2}$ years.
The difference between the compound interest and the simple interest on a principal sum of $₹24,000$ in $2$ years at same rate of interest is $₹60$. The rate of interest is:
The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. The rate of interest per annum is?
A sum of Rs. 2000 amounts to Rs. 4000 in two years at compound interest. In how many years does the same amount becomes Rs. 8000?
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, the compound interest on the same at the same rate and for the same time is: