To find the compound interest, we first need to calculate the total amount after the specified period.
Since the interest is compounded quarterly, we need to adjust the annual rate and the time period:
The formula for the amount (A) when compounded is:
$A = P \times (1 + r)^n$
Substitute the values:
$A = 1200 \times (1 + 0.03)^2$
$A = 1200 \times (1.03)^2$
$A = 1200 \times 1.0609$
$A = 1273.08$
The compound interest is the difference between the final amount and the principal amount:
$CI = A - P$
$CI = ₹1273.08 - ₹1200$
$CI = ₹73.08$
The compound interest is ₹73.08.
Find the interest (in ₹) on ₹8,000 at 10% per annum compounded half yearly for $1\frac{1}{2}$ years.
The difference between the compound interest and the simple interest on a principal sum of $₹24,000$ in $2$ years at same rate of interest is $₹60$. The rate of interest is:
Amit had invested same amount of sums at simple as well as compound interest, compounded annually. The time period of investment for both the sums was 2 years and rate of interest too was the same, 4% per annum. At the end, he found a difference of ₹43 in both the interests received. What were the sums (in ₹) invested?
When the difference between compound interest, compounded annually, and simple interest for three years is ₹186 at 10% interest per annum, the principal is ₹______.