To find the compound interest, we first need to calculate the total amount after the specified period.
Since the interest is compounded quarterly, we need to adjust the annual rate and the time period:
The formula for the amount (A) when compounded is:
$A = P \times (1 + r)^n$
Substitute the values:
$A = 1200 \times (1 + 0.03)^2$
$A = 1200 \times (1.03)^2$
$A = 1200 \times 1.0609$
$A = 1273.08$
The compound interest is the difference between the final amount and the principal amount:
$CI = A - P$
$CI = ₹1273.08 - ₹1200$
$CI = ₹73.08$
The compound interest is ₹73.08.
Find the interest (in ₹) on ₹8,000 at 10% per annum compounded half yearly for $1\frac{1}{2}$ years.
The difference between the compound interest and the simple interest on a principal sum of $₹24,000$ in $2$ years at same rate of interest is $₹60$. The rate of interest is:
The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. The rate of interest per annum is?
A sum of Rs. 2000 amounts to Rs. 4000 in two years at compound interest. In how many years does the same amount becomes Rs. 8000?
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, the compound interest on the same at the same rate and for the same time is: