The question asks for the compound interest (CI) on a sum, given the simple interest (SI) details for the same sum, rate, and time period.
First, we need to find the principal amount (P) using the given simple interest (SI), rate (R), and time (T).
The formula for Simple Interest is:
$ SI = \frac{P \times R \times T}{100} $
Substitute the given values:
$ 50 = \frac{P \times 5 \times 2}{100} $
$ 50 = \frac{P \times 10}{100} $
$ 50 = \frac{P}{10} $
Solve for P:
$ P = 50 \times 10 $
$ P = 500 $
The principal sum is ₹500.
Now, we calculate the compound interest (CI) for the same principal, rate, and time.
The formula for Compound Interest is:
$ CI = P \left(1 + \frac{R}{100}\right)^T - P $
Substitute the values:
$ CI = 500 \left(1 + \frac{5}{100}\right)^2 - 500 $
$ CI = 500 \left(1 + 0.05\right)^2 - 500 $
$ CI = 500 \left(1.05\right)^2 - 500 $
Calculate the square of 1.05:
$ (1.05)^2 = 1.1025 $
Continue the calculation for CI:
$ CI = 500 \times 1.1025 - 500 $
$ CI = 551.25 - 500 $
$ CI = 51.25 $
The compound interest is ₹51.25.
Find the interest (in ₹) on ₹8,000 at 10% per annum compounded half yearly for $1\frac{1}{2}$ years.
The difference between the compound interest and the simple interest on a principal sum of $₹24,000$ in $2$ years at same rate of interest is $₹60$. The rate of interest is:
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A sum of Rs. 2000 amounts to Rs. 4000 in two years at compound interest. In how many years does the same amount becomes Rs. 8000?
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, the compound interest on the same at the same rate and for the same time is: