The question asks for the compound interest (CI) on a sum, given the simple interest (SI) details for the same sum, rate, and time period.
First, we need to find the principal amount (P) using the given simple interest (SI), rate (R), and time (T).
The formula for Simple Interest is:
$ SI = \frac{P \times R \times T}{100} $
Substitute the given values:
$ 50 = \frac{P \times 5 \times 2}{100} $
$ 50 = \frac{P \times 10}{100} $
$ 50 = \frac{P}{10} $
Solve for P:
$ P = 50 \times 10 $
$ P = 500 $
The principal sum is ₹500.
Now, we calculate the compound interest (CI) for the same principal, rate, and time.
The formula for Compound Interest is:
$ CI = P \left(1 + \frac{R}{100}\right)^T - P $
Substitute the values:
$ CI = 500 \left(1 + \frac{5}{100}\right)^2 - 500 $
$ CI = 500 \left(1 + 0.05\right)^2 - 500 $
$ CI = 500 \left(1.05\right)^2 - 500 $
Calculate the square of 1.05:
$ (1.05)^2 = 1.1025 $
Continue the calculation for CI:
$ CI = 500 \times 1.1025 - 500 $
$ CI = 551.25 - 500 $
$ CI = 51.25 $
The compound interest is ₹51.25.
Find the interest (in ₹) on ₹8,000 at 10% per annum compounded half yearly for $1\frac{1}{2}$ years.
The difference between the compound interest and the simple interest on a principal sum of $₹24,000$ in $2$ years at same rate of interest is $₹60$. The rate of interest is:
Amit had invested same amount of sums at simple as well as compound interest, compounded annually. The time period of investment for both the sums was 2 years and rate of interest too was the same, 4% per annum. At the end, he found a difference of ₹43 in both the interests received. What were the sums (in ₹) invested?
When the difference between compound interest, compounded annually, and simple interest for three years is ₹186 at 10% interest per annum, the principal is ₹______.