The question asks for the compound interest (CI) on a sum, given the simple interest (SI) details for the same sum, rate, and time period.
First, we need to find the principal amount (P) using the given simple interest (SI), rate (R), and time (T).
The formula for Simple Interest is:
$ SI = \frac{P \times R \times T}{100} $
Substitute the given values:
$ 50 = \frac{P \times 5 \times 2}{100} $
$ 50 = \frac{P \times 10}{100} $
$ 50 = \frac{P}{10} $
Solve for P:
$ P = 50 \times 10 $
$ P = 500 $
The principal sum is ₹500.
Now, we calculate the compound interest (CI) for the same principal, rate, and time.
The formula for Compound Interest is:
$ CI = P \left(1 + \frac{R}{100}\right)^T - P $
Substitute the values:
$ CI = 500 \left(1 + \frac{5}{100}\right)^2 - 500 $
$ CI = 500 \left(1 + 0.05\right)^2 - 500 $
$ CI = 500 \left(1.05\right)^2 - 500 $
Calculate the square of 1.05:
$ (1.05)^2 = 1.1025 $
Continue the calculation for CI:
$ CI = 500 \times 1.1025 - 500 $
$ CI = 551.25 - 500 $
$ CI = 51.25 $
The compound interest is ₹51.25.
Find the interest (in ₹) on ₹8,000 at 10% per annum compounded half yearly for $1\frac{1}{2}$ years.
The difference between the simple interest and the compound interest, compounded annually, on a certain sum of money for 2 years at 17% per annum is ₹967. Find the sum [rounded off to the nearest integer].