The question asks for the sum of money (Principal, P) given the difference between compound interest (CI) and simple interest (SI) for 2 years at a specific rate.
We are given:
For a time period of 2 years, the difference between compound interest and simple interest is given by the formula:
Difference = $P \times \left( \frac{R}{100} \right)^2$
Where P is the Principal sum.
$240 = P \times \left( \frac{8}{100} \right)^2$
$\frac{8}{100} = \frac{2}{25}$
$240 = P \times \left( \frac{2}{25} \right)^2$
$240 = P \times \frac{4}{625}$
$P = 240 \times \frac{625}{4}$
$P = 60 \times 625$
$P = 37,500$
Therefore, the sum of money is ₹37,500.
Find the interest (in ₹) on ₹8,000 at 10% per annum compounded half yearly for $1\frac{1}{2}$ years.
The difference between the compound interest and the simple interest on a principal sum of $₹24,000$ in $2$ years at same rate of interest is $₹60$. The rate of interest is:
Amit had invested same amount of sums at simple as well as compound interest, compounded annually. The time period of investment for both the sums was 2 years and rate of interest too was the same, 4% per annum. At the end, he found a difference of ₹43 in both the interests received. What were the sums (in ₹) invested?
When the difference between compound interest, compounded annually, and simple interest for three years is ₹186 at 10% interest per annum, the principal is ₹______.