The problem involves finding the annual compound interest rate given the amounts at the end of the first and second years.
Interest Earned (Year 2) = Amount (Year 2) - Amount (Year 1)
Interest Earned (Year 2) = ₹550 - ₹500 = ₹50
$R = \frac{\text{Interest Earned}}{\text{Principal Amount}} \times 100$
$R = \frac{50}{500} \times 100$
$R = \frac{1}{10} \times 100$
$R = 10\%$
Therefore, the rate of compound interest is 10% per annum.
Find the interest (in ₹) on ₹8,000 at 10% per annum compounded half yearly for $1\frac{1}{2}$ years.
The difference between the compound interest and the simple interest on a principal sum of $₹24,000$ in $2$ years at same rate of interest is $₹60$. The rate of interest is:
The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. The rate of interest per annum is?
A sum of Rs. 2000 amounts to Rs. 4000 in two years at compound interest. In how many years does the same amount becomes Rs. 8000?
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, the compound interest on the same at the same rate and for the same time is: