This question requires calculating the compound interest (CI) on a given principal amount over a specific period and rate.
The formula to calculate the total amount (A) after compound interest is applied is:
$ A = P \left( 1 + \frac{R}{100} \right)^T $
Substitute the given values:
$ A = 7500 \left( 1 + \frac{4}{100} \right)^2 $
$ A = 7500 \left( 1 + 0.04 \right)^2 $
$ A = 7500 \left( 1.04 \right)^2 $
$ A = 7500 \times 1.0816 $
$ A = 8112 $
The compound interest (CI) is the difference between the final amount (A) and the principal (P):
$ CI = A - P $
$ CI = 8112 - 7500 $
$ CI = 612 $
The compound interest is ₹612.
Find the interest (in ₹) on ₹8,000 at 10% per annum compounded half yearly for $1\frac{1}{2}$ years.
The difference between the compound interest and the simple interest on a principal sum of $₹24,000$ in $2$ years at same rate of interest is $₹60$. The rate of interest is:
The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. The rate of interest per annum is?
A sum of Rs. 2000 amounts to Rs. 4000 in two years at compound interest. In how many years does the same amount becomes Rs. 8000?
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, the compound interest on the same at the same rate and for the same time is: