The problem asks for the principal sum invested when the difference between compound interest (CI) and simple interest (SI) over 2 years is given, along with the interest rate.
We are given:
The formula for the difference between compound interest and simple interest for 2 years is:
\begin{equation*} \text{Difference} = P \times \left(\frac{R}{100}\right)^2 \end{equation*}
Where P is the principal sum.
Substitute the given values into the formula:
\begin{equation*} 47 = P \times \left(\frac{4}{100}\right)^2 \end{equation*}
Simplify the rate fraction:
\begin{equation*} \frac{4}{100} = \frac{1}{25} \end{equation*}
Now, substitute this back into the equation:
\begin{equation*} 47 = P \times \left(\frac{1}{25}\right)^2 \end{equation*}
\begin{equation*} 47 = P \times \frac{1}{625} \end{equation*}
To find P, rearrange the equation:
\begin{equation*} P = 47 \times 625 \end{equation*}
Calculate the final value:
\begin{equation*} P = 29,375 \end{equation*}
Therefore, the sum invested in each case is ₹29,375.
The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. The rate of interest per annum is?
A sum of Rs. 2000 amounts to Rs. 4000 in two years at compound interest. In how many years does the same amount becomes Rs. 8000?
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, the compound interest on the same at the same rate and for the same time is: