What will be the amount payable on the same sum at the rate of 8.5% per annum simple interest in $4\frac{5}{9}$ years?
This problem asks us to first find the initial sum of money (principal) based on the simple interest earned over a specific period at a given rate. Then, using this principal, we need to calculate the total amount payable (principal plus interest) for a different time period and interest rate.
We are given the simple interest (SI), the time period (T), and the annual interest rate (R) for the first scenario. We can use the simple interest formula to find the principal sum (P).
The formula for Simple Interest is:
$ SI = \frac{P \times R \times T}{100} $
Where:
First, let's convert the time period into an improper fraction:
$ T = 2\frac{6}{7} = \frac{(2 \times 7) + 6}{7} = \frac{14 + 6}{7} = \frac{20}{7} \text{ years} $
Now, we rearrange the formula to solve for P:
$ P = \frac{SI \times 100}{R \times T} $
Substitute the given values:
$ P = \frac{1188 \times 100}{7.7 \times \frac{20}{7}} $
Calculate the denominator ($R \times T$):
$ R \times T = 7.7 \times \frac{20}{7} = \frac{77}{10} \times \frac{20}{7} = \frac{11 \times 7}{10} \times \frac{2 \times 10}{7} = 11 \times 2 = 22 $
Now, calculate the Principal (P):
$ P = \frac{118800}{22} $
$ P = 5400 $
So, the Principal Sum is ₹5,400.
Now we use the principal sum calculated in Step 1 (P = ₹5,400) to find the simple interest for the second scenario. The new rate and time period are given.
Given for the second scenario:
Convert the time period into an improper fraction:
$ T = 4\frac{5}{9} = \frac{(4 \times 9) + 5}{9} = \frac{36 + 5}{9} = \frac{41}{9} \text{ years} $
Using the simple interest formula again:
$ SI = \frac{P \times R \times T}{100} $
Substitute the values:
$ SI = \frac{5400 \times 8.5 \times \frac{41}{9}}{100} $
Simplify the calculation:
$ SI = \frac{5400 \times \frac{85}{10} \times \frac{41}{9}}{100} $
$ SI = \frac{54 \times 85 \times 41}{9 \times 10} $
$ SI = \frac{6 \times 85 \times 41}{10} \quad (\text{since } 54 \div 9 = 6) $
$ SI = \frac{510 \times 41}{10} $
$ SI = 51 \times 41 $
$ SI = 2091 $
The Simple Interest for the second scenario is ₹2,091.
The total amount payable is the sum of the principal amount and the simple interest calculated for the second scenario.
Amount (A) = Principal (P) + Simple Interest (SI)
$ A = P + SI $
Substitute the values we found:
$ A = 5400 + 2091 $
$ A = 7491 $
Therefore, the total amount payable is ₹7,491.
The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. The rate of interest per annum is?
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If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, the compound interest on the same at the same rate and for the same time is: