The problem asks for the rate of interest (R) given the principal amount (P), time period (n), and the difference between Compound Interest (CI) and Simple Interest (SI) for 2 years.
Given:
For a period of 2 years, the difference between compound interest and simple interest is given by the formula:
Difference = $ P \left( \frac{R}{100} \right)^2 $
Where:
Substitute the given values into the formula:
$ 1000 = 16000 \left( \frac{R}{100} \right)^2 $
Now, we need to solve for R:
Therefore, the rate of interest is 25% per annum.
Find the interest (in ₹) on ₹8,000 at 10% per annum compounded half yearly for $1\frac{1}{2}$ years.
The difference between the simple interest and the compound interest, compounded annually, on a certain sum of money for 2 years at 17% per annum is ₹967. Find the sum [rounded off to the nearest integer].