The problem asks for the rate of interest (R) given the principal amount (P), time period (n), and the difference between Compound Interest (CI) and Simple Interest (SI) for 2 years.
Given:
For a period of 2 years, the difference between compound interest and simple interest is given by the formula:
Difference = $ P \left( \frac{R}{100} \right)^2 $
Where:
Substitute the given values into the formula:
$ 1000 = 16000 \left( \frac{R}{100} \right)^2 $
Now, we need to solve for R:
Therefore, the rate of interest is 25% per annum.
Find the interest (in ₹) on ₹8,000 at 10% per annum compounded half yearly for $1\frac{1}{2}$ years.
The difference between the compound interest and the simple interest on a principal sum of $₹24,000$ in $2$ years at same rate of interest is $₹60$. The rate of interest is:
The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. The rate of interest per annum is?
A sum of Rs. 2000 amounts to Rs. 4000 in two years at compound interest. In how many years does the same amount becomes Rs. 8000?
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, the compound interest on the same at the same rate and for the same time is: