Let ABC, PQR be two congruent triangles such that angle A = angle P = 90°. If BC = 13 cm, PR = 5 cm, find AB.

ΔABC ~ ΔDEF and the perimeters of ΔABC and ΔDEF are 40 cm and 12 cm, respectively. If DE = 6 cm, then AB is:  

ΔABC ∼ ΔPQR, ar (ΔABC) = 16 cm² and ar (ΔPQR) = 25 cm². If BC = 20 cm, then QR is equal to :

In a ΔABC, DE ∥ BC, where D is a point on AB and E is a point on AC. If DE divides the area of ΔABC into two equal parts, then DB ∶ AB is equal to :

The centroid of an equilateral triangle PQR is L. If PQ = 6 cm, the length of PL is:

From the circumcentre L of ΔXYZ, perpendicular LM is drawn on side YZ. If ∠YXZ = 60°, then the measure of ∠YLM is :

In an equilateral triangle ABC, D is the midpoint of side BC. If the length of BC is 8 cm, then the height of the triangle is:

If Δ ABC~Δ FDE such that AB = 9 cm, AC = 11 cm, DF = 16 cm and DE = 12 cm, then the length of BC is:

In a ΔABC, the median BE intersects AC at E. If BG = 12 cm, where G is the centroid, then BE is equal to:

The radius of the circumcircle of an equilateral triangle of √3 unit side, is:

If the ratio of the angles of a triangle is 3 : 5 : 7, find the value of the largest angle.

A. 36°

B. 60°

C. 84°

D. 15°

If ΔABC and Δ PQR are similar and \(\rm\frac{BC}{QR} = \frac{1}{3}\) , find  \(\rm\frac{ar(\Delta PQR)} {ar(\Delta BCA)}\)

If the angles of a triangle are in the ratio of 2 : 5 : 8, then find the value of the smallest angle.