If the ratio of corresponding sides of two similar triangles\(\sqrt{5} : \sqrt{7}\) is then what is the ratio of the area of the two triangles?
5 : 7
Understanding the relationship between the sides and areas of similar triangles is a fundamental concept in geometry. When two triangles are similar, their corresponding angles are equal, and their corresponding sides are in proportion. There is a specific theorem that connects the ratio of their corresponding sides to the ratio of their areas.
The theorem states that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
Let \(\triangle ABC\) and \(\triangle DEF\) be two similar triangles, denoted as \(\triangle ABC \sim \triangle DEF\). If \(s_1\) and \(s_2\) are the lengths of any pair of corresponding sides (for example, \(AB\) and \(DE\)), and \(A_1\) and \(A_2\) are their respective areas (Area(\(\triangle ABC\)) and Area(\(\triangle DEF\))), then the theorem can be expressed as:
\[ \frac{\text{Area}(\triangle ABC)}{\text{Area}(\triangle DEF)} = \left(\frac{AB}{DE}\right)^2 = \left(\frac{BC}{EF}\right)^2 = \left(\frac{AC}{DF}\right)^2 = \left(\frac{s_1}{s_2}\right)^2 \]
The question provides the ratio of the corresponding sides of two similar triangles. Let this ratio be \(s_1 : s_2\).
Given ratio of corresponding sides \( = \sqrt{5} : \sqrt{7} \)
This can be written as a fraction:
\[ \frac{s_1}{s_2} = \frac{\sqrt{5}}{\sqrt{7}} \]
We want to find the ratio of the areas of these two similar triangles. Let the areas be \(A_1\) and \(A_2\). According to the theorem on the areas of similar triangles, the ratio of their areas is the square of the ratio of their corresponding sides.
\[ \frac{A_1}{A_2} = \left(\frac{s_1}{s_2}\right)^2 \]
Substitute the given ratio of sides into this formula:
\[ \frac{A_1}{A_2} = \left(\frac{\sqrt{5}}{\sqrt{7}}\right)^2 \]
Now, calculate the square of the ratio:
\[ \left(\frac{\sqrt{5}}{\sqrt{7}}\right)^2 = \frac{(\sqrt{5})^2}{(\sqrt{7})^2} \]
The square of a square root is the number itself:
\[ (\sqrt{5})^2 = 5 \] \[ (\sqrt{7})^2 = 7 \]
So, the ratio of the areas is:
\[ \frac{A_1}{A_2} = \frac{5}{7} \]
The ratio of the area of the two triangles is \(5 : 7\).
Let's compare our calculated ratio with the given options:
The ratio of the areas of the two similar triangles is \(5 : 7\).
| Concept | Similar Triangles Property |
|---|---|
| Ratio of Corresponding Sides | \(s_1 : s_2\) |
| Ratio of Areas | \(A_1 : A_2 = (s_1/s_2)^2\) |
| Given Side Ratio | \(\sqrt{5} : \sqrt{7}\) |
| Calculated Area Ratio | \((\sqrt{5}/\sqrt{7})^2 = 5/7\) |
| Property | Ratio Relationship | Example |
|---|---|---|
| Corresponding Sides | \(a:b\) | Given as \(\sqrt{5}:\sqrt{7}\) |
| Corresponding Altitudes | \(a:b\) | Same as side ratio |
| Corresponding Medians | \(a:b\) | Same as side ratio |
| Corresponding Angle Bisectors | \(a:b\) | Same as side ratio |
| Perimeters | \(a:b\) | Same as side ratio |
| Areas | \(a^2:b^2\) | (\(\sqrt{5}\))^2 : (\(\sqrt{7}\))^2 = 5:7 |
Similar triangles have several important properties:
These properties are very useful for solving problems involving similar triangles, allowing us to find unknown lengths or areas if we know the scale factor or other ratios.
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