If the areas of two similar triangles are in the ratio 196 : 625, what would be the ratio of the corresponding sides?
14 ∶ 25
The question asks us to find the ratio of the corresponding sides of two similar triangles, given that the ratio of their areas is 196 : 625.
When two triangles are similar, there is a special relationship between the ratio of their areas and the ratio of their corresponding sides. This relationship is a fundamental theorem in geometry concerning similar figures.
The theorem states that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
Let $\triangle ABC$ and $\triangle DEF$ be two similar triangles ($\triangle ABC \sim \triangle DEF$). Let their areas be Area($\triangle ABC$) and Area($\triangle DEF$). Let $AB$ and $DE$ be a pair of corresponding sides, $BC$ and $EF$ another pair, and $AC$ and $DF$ the third pair.
According to the theorem:
$$ \frac{\text{Area}(\triangle ABC)}{\text{Area}(\triangle DEF)} = \left(\frac{AB}{DE}\right)^2 = \left(\frac{BC}{EF}\right)^2 = \left(\frac{AC}{DF}\right)^2 $$
This means if the ratio of corresponding sides is $s_1 : s_2$, then the ratio of their areas is $s_1^2 : s_2^2$. Conversely, if the ratio of areas is $A_1 : A_2$, then the ratio of corresponding sides is $\sqrt{A_1} : \sqrt{A_2}$.
Given the ratio of the areas of the two similar triangles is 196 : 625. Let this ratio be $\frac{\text{Area}_1}{\text{Area}_2} = \frac{196}{625}$.
Let the ratio of their corresponding sides be $\frac{s_1}{s_2}$.
Using the theorem, we have:
$$ \frac{\text{Area}_1}{\text{Area}_2} = \left(\frac{s_1}{s_2}\right)^2 $$
Substitute the given area ratio:
$$ \frac{196}{625} = \left(\frac{s_1}{s_2}\right)^2 $$
To find the ratio of the sides $\frac{s_1}{s_2}$, we need to take the square root of both sides of the equation:
$$ \frac{s_1}{s_2} = \sqrt{\frac{196}{625}} $$
Now, we calculate the square roots of the numerator and the denominator:
So, the ratio of the corresponding sides is:
$$ \frac{s_1}{s_2} = \frac{14}{25} $$
The ratio of the corresponding sides is 14 : 25.
Let's compare our calculated ratio with the given options:
| Option | Ratio |
|---|---|
| 1 | 14 ∶ 25 |
| 2 | 13 ∶ 20 |
| 3 | 14 ∶ 20 |
| 4 | 13 ∶ 25 |
Our calculated ratio, 14 : 25, matches Option 1.
Based on the theorem relating the areas and corresponding sides of similar triangles, the ratio of the corresponding sides is the square root of the ratio of their areas. Given the area ratio 196 : 625, the side ratio is $\sqrt{196} : \sqrt{625}$, which simplifies to 14 : 25.
| Property | Ratio Relationship |
|---|---|
| Ratio of Corresponding Sides ($s_1 : s_2$) | Given as $s_1 : s_2$ |
| Ratio of Corresponding Heights ($h_1 : h_2$) | Equals the ratio of corresponding sides ($s_1 : s_2$) |
| Ratio of Corresponding Medians ($m_1 : m_2$) | Equals the ratio of corresponding sides ($s_1 : s_2$) |
| Ratio of Corresponding Angle Bisectors ($b_1 : b_2$) | Equals the ratio of corresponding sides ($s_1 : s_2$) |
| Ratio of Perimeters ($P_1 : P_2$) | Equals the ratio of corresponding sides ($s_1 : s_2$) |
| Ratio of Areas ($A_1 : A_2$) | Equals the square of the ratio of corresponding sides ($\left(s_1/s_2\right)^2$ or $s_1^2 : s_2^2$) |
Similar triangles are triangles that have the same shape but different sizes. Their corresponding angles are equal, and their corresponding sides are in proportion.
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