If ∆ABC ~ ∆EDF such that AB = 6 cm, DF = 16 cm and DE = 8 cm, then the length of BC is:
12 cm
The question asks us to find the length of side BC in triangle ABC, given that triangle ABC is similar to triangle EDF ($\Delta ABC \sim \Delta EDF$) and provided the lengths of sides AB, DF, and DE.
Similarity between two triangles is a fundamental concept in geometry. When two triangles are similar, it means they have the same shape but not necessarily the same size. This similarity implies two main properties:
The notation $\Delta ABC \sim \Delta EDF$ is crucial for identifying the corresponding sides. The order of the vertices in the notation tells us which vertices correspond to each other:
Based on these corresponding vertices, we can determine the corresponding sides:
Since the triangles are similar, the ratio of their corresponding sides is equal. We can write this as:
$$ \frac{AB}{ED} = \frac{BC}{DF} = \frac{AC}{EF} $$
We are given the following lengths:
We need to find the length of BC. Looking at the ratio equation, we can use the part that involves the known lengths and the unknown BC:
$$ \frac{AB}{ED} = \frac{BC}{DF} $$
Now, let's substitute the given values into the proportion:
$$ \frac{6}{8} = \frac{BC}{16} $$
To solve for BC, we can cross-multiply or multiply both sides of the equation by 16:
$$ BC = \frac{6}{8} \times 16 $$
Simplify the fraction $\frac{6}{8}$ to $\frac{3}{4}$:
$$ BC = \frac{3}{4} \times 16 $$
Now, perform the multiplication:
$$ BC = 3 \times \frac{16}{4} $$
$$ BC = 3 \times 4 $$
$$ BC = 12 \text{ cm} $$
Thus, the length of BC is 12 cm.
| Given | Ratio | Substitution | Calculation | Result |
|---|---|---|---|---|
| AB = 6 cm DE = 8 cm DF = 16 cm |
$\frac{AB}{ED} = \frac{BC}{DF}$ | $\frac{6}{8} = \frac{BC}{16}$ | $BC = \frac{6}{8} \times 16 = \frac{3}{4} \times 16 = 12$ | BC = 12 cm |
Based on the property of similar triangles that the ratio of corresponding sides is equal, and using the given lengths AB = 6 cm, DE = 8 cm, and DF = 16 cm, we calculated the length of BC to be 12 cm.
| Concept | Description | Key Property |
|---|---|---|
| Similar Triangles | Triangles with the same shape but possibly different sizes. | Corresponding angles are equal; ratio of corresponding sides is constant. |
| Corresponding Sides | Pairs of sides opposite corresponding angles, identified by the order of vertices in the similarity statement. | Their ratio is constant across all pairs of corresponding sides. |
The constant ratio between corresponding sides of similar triangles is called the scale factor. In this problem, the ratio $\frac{AB}{ED} = \frac{6}{8} = \frac{3}{4}$. This means that triangle ABC is $\frac{3}{4}$ times the size of triangle EDF in terms of side lengths. Conversely, triangle EDF is $\frac{ED}{AB} = \frac{8}{6} = \frac{4}{3}$ times the size of triangle ABC.
We found BC = 12 cm and DF = 16 cm. Let's check the ratio $\frac{BC}{DF} = \frac{12}{16} = \frac{3}{4}$. This confirms our calculation and the consistency of the scale factor.
The concept of scale factor is useful for finding any unknown side length if at least one pair of corresponding sides is known, providing the scale factor. It is also related to the ratio of areas (ratio of sides squared) and perimeters (same as ratio of sides).
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