Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
The problem asks us to simplify the mathematical expression: \(441 \div \left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\). To solve this, we must follow the order of operations, often remembered by acronyms like BODMAS or PEMDAS.
This means we first evaluate expressions inside brackets `[ ]`, then parentheses `( )`, followed by division and multiplication (from left to right), and finally addition and subtraction (from left to right).
There are three parts inside the main bracket `[ ]` that involve inner parentheses or fractions requiring immediate attention:
\(270 \div \frac{3}{7} = 270 \times \frac{7}{3}\)
We can simplify this: \(270/3 = 90\). So, \(90 \times 7 = 630\).
\(17 \div \frac{1}{3} = 17 \times 3 = 51\).
\(8\frac{1}{2} = \frac{(8 \times 2) + 1}{2} = \frac{16 + 1}{2} = \frac{17}{2}\).
Now perform the subtraction: \(\frac{17}{2} - \frac{5}{2} = \frac{17 - 5}{2} = \frac{12}{2} = 6\).
Now, replace the calculated values back into the original expression inside the square brackets:
The expression inside the bracket was \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\).
Substituting the results from Step 1:
\(\left[630 + 51 - 6\right]\)
Perform the addition and subtraction within the bracket from left to right:
\(630 + 51 = 681\)
\(681 - 6 = 675\)
So, the value inside the square bracket is \(675\).
The original expression is \(441 \div \left[\text{result from bracket}\right]\).
\(441 \div 675\)
We need to express this division as a fraction and simplify it if possible.
\(\frac{441}{675}\)
Let's find common factors for the numerator (441) and the denominator (675). We can check divisibility by small prime numbers.
Sum of digits for 441: \(4+4+1 = 9\). 9 is divisible by 3, so 441 is divisible by 3. \(441 \div 3 = 147\).
Sum of digits for 675: \(6+7+5 = 18\). 18 is divisible by 3, so 675 is divisible by 3. \(675 \div 3 = 225\).
The fraction becomes \(\frac{147}{225}\).
Sum of digits for 147: \(1+4+7 = 12\). 12 is divisible by 3, so 147 is divisible by 3. \(147 \div 3 = 49\).
Sum of digits for 225: \(2+2+5 = 9\). 9 is divisible by 3, so 225 is divisible by 3. \(225 \div 3 = 75\).
The fraction becomes \(\frac{49}{75}\).
Now check if 49 and 75 have any common factors. The factors of 49 are 1, 7, 49. The factors of 75 are 1, 3, 5, 15, 25, 75. They have no common factors other than 1.
So, the simplified fraction is \(\frac{49}{75}\).
Putting it all together:
| Expression | Calculation | Result |
| \(270 \div \frac{3}{7}\) | \(270 \times \frac{7}{3}\) | 630 |
| \(17 \div \frac{1}{3}\) | \(17 \times 3\) | 51 |
| \(8\frac{1}{2} - \frac{5}{2}\) | \(\frac{17}{2} - \frac{5}{2} = \frac{12}{2}\) | 6 |
| \(\left[630 + 51 - 6\right]\) | \(681 - 6\) | 675 |
| \(441 \div 675\) | \(\frac{441}{675} = \frac{147}{225} = \frac{49}{75}\) | \(\frac{49}{75}\) |
The simplified expression is \(\frac{49}{75}\).
| Concept | Description | Example |
| Order of Operations | Sequence to follow when evaluating expressions: Parentheses/Brackets, Exponents, Multiplication/Division (L to R), Addition/Subtraction (L to R). | \(2 + 3 \times 4 = 2 + 12 = 14\) (Multiplication before Addition) |
| Dividing by a Fraction | Multiply by the reciprocal of the divisor. | \(a \div \frac{b}{c} = a \times \frac{c}{b}\) |
| Mixed Numbers | Convert to improper fractions before performing arithmetic operations. | \(a\frac{b}{c} = \frac{a \times c + b}{c}\) |
| Simplifying Fractions | Divide the numerator and denominator by their greatest common divisor (GCD). | \(\frac{12}{18} = \frac{12 \div 6}{18 \div 6} = \frac{2}{3}\) |
Understanding the correct order of operations is crucial for simplifying complex mathematical expressions accurately. The acronyms BODMAS (Brackets, Orders, Division and Multiplication, Addition and Subtraction) or PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction) help remember the sequence.
In the problem solved, we meticulously followed these rules, starting with the innermost parentheses and working outwards, performing divisions, subtractions, and additions in the correct order to arrive at the simplified fraction.
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