The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is:
To find the value of the given mathematical expression, we need to follow the order of operations, often remembered by the acronym BODMAS or PEMDAS. This rule dictates the sequence in which operations should be performed:
The expression is: \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\)
Let's simplify the expression step by step according to the BODMAS rule.
We start with the expression inside the parentheses: \((\frac{3}{4}-\frac{1}{3})\). To subtract fractions, we need a common denominator. The least common multiple (LCM) of 4 and 3 is 12.
\(\frac{3}{4}-\frac{1}{3} = \frac{3 \times 3}{4 \times 3}-\frac{1 \times 4}{3 \times 4} = \frac{9}{12}-\frac{4}{12} = \frac{9-4}{12} = \frac{5}{12}\)
The expression inside the bracket becomes: \( [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{5}{12})\;of\;\frac{2}{9}] \)
Next, we handle the 'of' operation. Recall that 'of' means multiplication. So, we calculate \((\frac{5}{12})\;of\;\frac{2}{9}\).
\(\frac{5}{12}\;of\;\frac{2}{9} = \frac{5}{12} \times \frac{2}{9} = \frac{5 \times 2}{12 \times 9} = \frac{10}{108}\)
We can simplify \(\frac{10}{108}\) by dividing both numerator and denominator by their greatest common divisor, which is 2.
\(\frac{10}{108} = \frac{10 \div 2}{108 \div 2} = \frac{5}{54}\)
The expression inside the bracket is now: \( [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div\frac{5}{54}] \)
According to BODMAS, division comes before addition. We need to calculate \(\frac{1}{6}\div\frac{5}{54}\). Dividing by a fraction is the same as multiplying by its reciprocal.
\(\frac{1}{6}\div\frac{5}{54} = \frac{1}{6} \times \frac{54}{5} = \frac{1 \times 54}{6 \times 5} = \frac{54}{30}\)
We can simplify \(\frac{54}{30}\) by dividing both numerator and denominator by their greatest common divisor, which is 6.
\(\frac{54}{30} = \frac{54 \div 6}{30 \div 6} = \frac{9}{5}\)
The expression inside the bracket is now: \( [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{9}{5}] \)
Now we need to add the fractions inside the bracket: \(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{9}{5}\). To add fractions, we find the LCM of their denominators (2, 3, 4, 5). The LCM is 60.
Convert each fraction to an equivalent fraction with a denominator of 60:
Now add the equivalent fractions:
\(\frac{30}{60}+\frac{20}{60}+\frac{15}{60}+\frac{108}{60} = \frac{30+20+15+108}{60} = \frac{173}{60}\)
The value inside the bracket is \(\frac{173}{60}\).
The original expression is now reduced to: \(9 \div \frac{173}{60}\)
Finally, we perform the division outside the bracket. Dividing by a fraction is the same as multiplying by its reciprocal.
\(9 \div \frac{173}{60} = 9 \times \frac{60}{173} = \frac{9 \times 60}{173} = \frac{540}{173}\)
The value of the expression is \(\frac{540}{173}\).
Let's check the options:
| Option | Value |
|---|---|
| 1 | \(\frac{540}{173}\) |
| 2 | \(\frac{340}{173}\) |
| 3 | \(\frac{480}{173}\) |
| 4 | \(\frac{2540}{173}\) |
Our calculated value matches Option 1.
| Step | Operation Type | Details |
|---|---|---|
| 1 | Brackets/Parentheses | Simplify expressions inside () first, then [] |
| 2 | Orders/Exponents | Calculate powers and roots |
| 3 | Division and Multiplication | Perform from left to right |
| 4 | Addition and Subtraction | Perform from left to right |
Working with fractions requires understanding basic operations:
Always simplify fractions to their lowest terms at the end, or during intermediate steps if it makes calculations easier.
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Column I | Column II | ||
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b. | Equivalent fraction of \(\frac{9}{15}\) is | ii. | Improper fraction |
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