All Exams Test series for 1 year @ ₹349 only
Question

What is the value of \(\rm \frac{X}{Y}\) if \(\rm \frac{X-5Y}{X+5Y}=\frac{7}{13}\).

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is \(\frac{50}{3}\)

Finding the Value of X/Y from a Given Equation

The problem asks us to find the value of the ratio \(\frac{X}{Y}\) given the equation involving \(X\) and \(Y\).

The given equation is:

\(\frac{X-5Y}{X+5Y}=\frac{7}{13}\)

To find the value of \(\frac{X}{Y}\), we need to rearrange this equation to isolate the ratio. We can do this by cross-multiplying.

Step-by-Step Solution to Find X/Y

Let's solve the given equation:

  1. Start with the given equation: \(\frac{X-5Y}{X+5Y}=\frac{7}{13}\)
  2. Cross-multiply the terms: \(13 \times (X-5Y) = 7 \times (X+5Y)\)
  3. Distribute the numbers on both sides: \(13X - 13 \times 5Y = 7X + 7 \times 5Y\)
  4. Simplify the multiplication: \(13X - 65Y = 7X + 35Y\)
  5. Now, collect the terms involving \(X\) on one side of the equation and the terms involving \(Y\) on the other side. Let's move \(7X\) to the left side and \(-65Y\) to the right side: \(13X - 7X = 35Y + 65Y\)
  6. Combine the like terms on both sides: \(6X = 100Y\)
  7. The goal is to find \(\frac{X}{Y}\). To get this ratio, we can divide both sides of the equation by \(Y\) (assuming \(Y \neq 0\)) and by 6. First, divide by \(Y\): \(\frac{6X}{Y} = 100\). Then, divide by 6: \(\frac{X}{Y} = \frac{100}{6}\)
  8. Finally, simplify the fraction \(\frac{100}{6}\) by dividing both the numerator and the denominator by their greatest common divisor, which is 2: \(\frac{100 \div 2}{6 \div 2} = \frac{50}{3}\)

Thus, the value of \(\frac{X}{Y}\) is \(\frac{50}{3}\).

Conclusion on the Value of X/Y

By solving the given algebraic equation \(\frac{X-5Y}{X+5Y}=\frac{7}{13}\) through cross-multiplication and rearrangement, we found that the ratio \(\frac{X}{Y}\) is equal to \(\frac{50}{3}\).

This matches one of the provided options.


Revision Table: Key Steps for Solving Ratio Equations

Step Description Application in this Problem
1 Identify the equation involving ratios. \(\frac{X-5Y}{X+5Y}=\frac{7}{13}\)
2 Cross-multiply to remove denominators. \(13(X-5Y) = 7(X+5Y)\)
3 Expand both sides. \(13X - 65Y = 7X + 35Y\)
4 Collect terms with the same variable. \(13X - 7X = 35Y + 65Y\)
5 Simplify the equation. \(6X = 100Y\)
6 Rearrange to isolate the desired ratio (X/Y). \(\frac{X}{Y} = \frac{100}{6}\)
7 Simplify the final ratio. \(\frac{50}{3}\)

Additional Information: Working with Ratios and Equations

A ratio is a comparison of two quantities by division. In this problem, we are working with the ratio of two variables, \(X\) and \(Y\).

When solving equations involving ratios or fractions, cross-multiplication is a fundamental technique. It helps convert the fractional equation into a linear equation, which is generally easier to solve.

The principle behind cross-multiplication is that if \(\frac{a}{b} = \frac{c}{d}\) (where \(b \neq 0\) and \(d \neq 0\)), then \(ad = bc\). This is derived by multiplying both sides of the equation by \(bd\).

Once the equation is linear (without fractions), the next step is usually to gather terms containing the variables you are interested in on one side and constant terms or other variables on the other side. This involves using inverse operations (addition/subtraction, multiplication/division).

Simplifying fractions at the end is crucial to present the answer in its simplest form.

Was this answer helpful?

Similar Questions

  1. Simplify the expression 441 ÷  \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)

  2. If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:

  3. Simplify the following expression.

    \([\frac{85}{34}\times \frac{1}{18}- \{(\frac{46}{69}\div\frac{27}{135})-(\frac{86}{129}\div\frac{14}{91})\}\ of \frac{112}{36}]\)

  4. The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\)  is:

  5. Simplify the following expression:

    \(\rm \frac{7}{12} \div \frac{1}{10} \ of \ \frac{2}{3} - \frac{5}{3} \times \frac{9}{10} + \frac{5}{8} \div \frac{3}{4} \ of \ \frac{2}{3}\)

  6. value of   \(3\frac{5}{6}+\left[3\frac{2}{3}+\lbrace{\frac{15}{4}\left(5\frac{4}{5}\div 14\frac{1}{2}\right)\rbrace}\right]\) is equal to:

  7. Three fractions x, y and z are such that x > y > z. When the smallest of them is divided by the greatest, the result is \({\frac{9}{16}}\) , which exceeds y by 0.0625. If x + y + z =  \(2{\frac{3}{12}}\) , then what is the value of x + z?

  8. The value of \(\frac{46+\frac{3}{4} \ \text{of}\ 32-6}{37-\frac{3}{4} \ \text{of}\ (34+6)}\) is:
  9. Raju ate \(\frac{3}{8}\)  part of a pizza and Adam ate  \(\frac{3}{10}\) part of the remaining pizza. Then Renu ate  \(\frac{4}{7}\)  part of the pizza that was left. What fraction of the pizza is still left?

  10. Evaluate:

    \(\frac 1 {15} + \frac 1 {35} + \frac 1 {63} + \frac 1 {99} + \frac 1 {143}\)


Important Questions from Fractions

  1. 5 \(\frac{3}{4}\) + x + 2  \(\frac{1}{2}\) = 10  \(\frac{1}{8}\) Find the value of x.

  2. Simplify the expression 441 ÷  \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)

  3. Number 0.232323 can be written in rational form as:

  4. Solve: \(\frac{1}{2}\)  [{-2(2 + 3)*20}/2]

  5. Match the following.

    Column I

    Column II

    a.

    Equivalent fraction of \(\frac{7}{12}\)  is  

    i.

    Proper fraction

    b.

    Equivalent fraction of  \(\frac{9}{15}\)  is

    ii.

    Improper fraction

    c.

    \(\frac{7}{11}\)  is

    iii.

    \(\frac{21}{36}\)

    d.

    \(\frac{19}{5}\)  is

    iv.

    \(\frac{3}{5}\)

Need Expert Advice?
Upcoming Exams
SSC CGL
September 30, 2026
UPSSSC PET
October 23, 2026
Test Series
SSC CGL img
SSC
SSC CGL (Tier I + Tier II) 2026 Mock Test Series - Latest Pattern
2503 Tests 6 Tests Free
5388 Attempts
4.2(868)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App