What is the value of \(\rm \frac{X}{Y}\) if \(\rm \frac{X-5Y}{X+5Y}=\frac{7}{13}\).
The problem asks us to find the value of the ratio \(\frac{X}{Y}\) given the equation involving \(X\) and \(Y\).
The given equation is:
\(\frac{X-5Y}{X+5Y}=\frac{7}{13}\)
To find the value of \(\frac{X}{Y}\), we need to rearrange this equation to isolate the ratio. We can do this by cross-multiplying.
Let's solve the given equation:
Thus, the value of \(\frac{X}{Y}\) is \(\frac{50}{3}\).
By solving the given algebraic equation \(\frac{X-5Y}{X+5Y}=\frac{7}{13}\) through cross-multiplication and rearrangement, we found that the ratio \(\frac{X}{Y}\) is equal to \(\frac{50}{3}\).
This matches one of the provided options.
| Step | Description | Application in this Problem |
|---|---|---|
| 1 | Identify the equation involving ratios. | \(\frac{X-5Y}{X+5Y}=\frac{7}{13}\) |
| 2 | Cross-multiply to remove denominators. | \(13(X-5Y) = 7(X+5Y)\) |
| 3 | Expand both sides. | \(13X - 65Y = 7X + 35Y\) |
| 4 | Collect terms with the same variable. | \(13X - 7X = 35Y + 65Y\) |
| 5 | Simplify the equation. | \(6X = 100Y\) |
| 6 | Rearrange to isolate the desired ratio (X/Y). | \(\frac{X}{Y} = \frac{100}{6}\) |
| 7 | Simplify the final ratio. | \(\frac{50}{3}\) |
A ratio is a comparison of two quantities by division. In this problem, we are working with the ratio of two variables, \(X\) and \(Y\).
When solving equations involving ratios or fractions, cross-multiplication is a fundamental technique. It helps convert the fractional equation into a linear equation, which is generally easier to solve.
The principle behind cross-multiplication is that if \(\frac{a}{b} = \frac{c}{d}\) (where \(b \neq 0\) and \(d \neq 0\)), then \(ad = bc\). This is derived by multiplying both sides of the equation by \(bd\).
Once the equation is linear (without fractions), the next step is usually to gather terms containing the variables you are interested in on one side and constant terms or other variables on the other side. This involves using inverse operations (addition/subtraction, multiplication/division).
Simplifying fractions at the end is crucial to present the answer in its simplest form.
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
Simplify the following expression.
\([\frac{85}{34}\times \frac{1}{18}- \{(\frac{46}{69}\div\frac{27}{135})-(\frac{86}{129}\div\frac{14}{91})\}\ of \frac{112}{36}]\)
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is:
Simplify the following expression:
\(\rm \frac{7}{12} \div \frac{1}{10} \ of \ \frac{2}{3} - \frac{5}{3} \times \frac{9}{10} + \frac{5}{8} \div \frac{3}{4} \ of \ \frac{2}{3}\)
value of \(3\frac{5}{6}+\left[3\frac{2}{3}+\lbrace{\frac{15}{4}\left(5\frac{4}{5}\div 14\frac{1}{2}\right)\rbrace}\right]\) is equal to:
Three fractions x, y and z are such that x > y > z. When the smallest of them is divided by the greatest, the result is \({\frac{9}{16}}\) , which exceeds y by 0.0625. If x + y + z = \(2{\frac{3}{12}}\) , then what is the value of x + z?
Raju ate \(\frac{3}{8}\) part of a pizza and Adam ate \(\frac{3}{10}\) part of the remaining pizza. Then Renu ate \(\frac{4}{7}\) part of the pizza that was left. What fraction of the pizza is still left?
Evaluate:
\(\frac 1 {15} + \frac 1 {35} + \frac 1 {63} + \frac 1 {99} + \frac 1 {143}\)
5 \(\frac{3}{4}\) + x + 2 \(\frac{1}{2}\) = 10 \(\frac{1}{8}\) Find the value of x.
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
Number 0.232323 can be written in rational form as:
Solve: \(\frac{1}{2}\) [{-2(2 + 3)*20}/2]
Match the following.
Column I | Column II | ||
a. | Equivalent fraction of \(\frac{7}{12}\) is | i. | Proper fraction |
b. | Equivalent fraction of \(\frac{9}{15}\) is | ii. | Improper fraction |
c. | \(\frac{7}{11}\) is | iii. | \(\frac{21}{36}\) |
d. | \(\frac{19}{5}\) is | iv. | \(\frac{3}{5}\) |