5 \(\frac{3}{4}\) + x + 2 \(\frac{1}{2}\) = 10 \(\frac{1}{8}\) Find the value of x.
The problem asks us to find the value of the variable x in the given equation involving mixed numbers.
The equation is:
\(5 \frac{3}{4} + x + 2 \frac{1}{2} = 10 \frac{1}{8}\)
It's often easier to work with improper fractions when solving equations. Let's convert each mixed number:
Substituting these into the equation, we get:
\(\frac{23}{4} + x + \frac{5}{2} = \frac{81}{8}\)
Let's add the fractions \(\frac{23}{4}\) and \(\frac{5}{2}\). To add fractions, they must have a common denominator. The least common multiple of 4 and 2 is 4.
Convert \(\frac{5}{2}\) to a fraction with a denominator of 4:
\(\frac{5}{2} = \frac{5 \times 2}{2 \times 2} = \frac{10}{4}\)
Now add the fractions:
\(\frac{23}{4} + \frac{10}{4} = \frac{23 + 10}{4} = \frac{33}{4}\)
The equation now becomes:
\(\frac{33}{4} + x = \frac{81}{8}\)
To find x, we need to subtract \(\frac{33}{4}\) from both sides of the equation:
\(x = \frac{81}{8} - \frac{33}{4}\)
To subtract the fractions, they need a common denominator. The least common multiple of 8 and 4 is 8.
Convert \(\frac{33}{4}\) to a fraction with a denominator of 8:
\(\frac{33}{4} = \frac{33 \times 2}{4 \times 2} = \frac{66}{8}\)
Now subtract:
\(x = \frac{81}{8} - \frac{66}{8} = \frac{81 - 66}{8} = \frac{15}{8}\)
The value of x is \(\frac{15}{8}\). To express this as a mixed number, divide the numerator (15) by the denominator (8):
\(15 \div 8 = 1\) with a remainder of \(15 - (1 \times 8) = 15 - 8 = 7\).
So, \(\frac{15}{8}\) as a mixed number is \(1 \frac{7}{8}\).
Thus, the value of x is \(1 \frac{7}{8}\).
We can check our answer by substituting \(x = 1 \frac{7}{8}\) back into the original equation.
\(5 \frac{3}{4} + 1 \frac{7}{8} + 2 \frac{1}{2}\)
Using improper fractions: \(\frac{23}{4} + \frac{15}{8} + \frac{5}{2}\)
Find a common denominator, which is 8:
\(\frac{23 \times 2}{4 \times 2} = \frac{46}{8}\)
\(\frac{5 \times 4}{2 \times 4} = \frac{20}{8}\)
Summing the fractions: \(\frac{46}{8} + \frac{15}{8} + \frac{20}{8} = \frac{46 + 15 + 20}{8} = \frac{81}{8}\)
Convert back to a mixed number: \(\frac{81}{8} = 10 \frac{1}{8}\).
This matches the right side of the original equation, confirming our value for x is correct.
The value of x is \(1 \frac{7}{8}\).
The value of \(\frac{5}{8}÷ (\frac{8}{11}\times2\frac{3}{4}÷\frac{4}{9})\) + \(5\frac{1}{3}\) ÷ \((5\frac{1}{4}\div\frac{3}{8}\times\frac{3}{7}) \) of \(1\frac{7}{9}\) is:
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