Statements regarding rectifier are : A. RMS value of current in a half wave rectifier is \(\frac{I_m}{\sqrt{2}}\) B. PIV of diode in a full wave bridge rectifier is Vm volts. C. TUF and rectification efficiency for a rectifier are same parametrs. D. Rectifier converts A.C. to rippled DC not pure D.C. Choose the correct answer from the options given below:
B & D only
Let's evaluate each statement related to rectifiers to determine which ones are correct.
- Statement A: RMS value of current in a half wave rectifier is \(\frac{I_m}{\sqrt{2}}\)
- The RMS (Root Mean Square) value of current for a half-wave rectifier is not \(\frac{I_m}{\sqrt{2}}\). In fact, it is given by \(\frac{I_m}{2}\) where \(I_m\) is the peak current.
- Statement B: PIV of diode in a full wave bridge rectifier is \(V_m\) volts.
- PIV (Peak Inverse Voltage) is the maximum reverse voltage a diode can withstand without breaking down. In a full-wave bridge rectifier, each diode in the bridge configuration must withstand a peak inverse voltage equal to \(V_m\), the peak voltage of the input AC signal.
- This statement is true.
- Statement C: TUF and rectification efficiency for a rectifier are same parameters.
- TUF (Transformer Utilization Factor) and rectification efficiency are different parameters.
- TUF measures the utilization of the transformer in a rectifier circuit, while rectification efficiency measures how effectively the rectifier converts AC to DC.
- This statement is false.
- Statement D: Rectifier converts A.C. to rippled DC not pure D.C.
- A rectifier indeed converts AC to a pulsating DC voltage, which still contains ripples.
- To smooth these ripples and obtain a steadier DC output, filters are often used following the rectification process.
- This statement is true.
Based on the evaluation of each statement, the correct statements are B and D. Therefore, the correct answer is:
B & D only
Similar Questions
Consider the following rectifier circuits :
1. Half-wave rectifier without filter
2. Full-wave rectifier without filter
3. Full-wave rectifier with series inductance filter
4. Full-wave rectifier with capacitance filterThe sequence of these rectifier circuits in decreasing order of the ripple factor is
Assertion (A) : Capacitor input filter gives a high output voltage which drops as the load is increased.
Reason (R) : Capacitor input filters produce more heating in the rectifiers.
For the different values of 'L' while keeping 'RL' as constant, following graph is obtained from the given circuit.
Choose the correct ascending order from the options given below for the different values of ' L ' :
The ratio of peak to peak input ripple voltage to peak to peak ripple output voltage is known as:
Read the statements:
A. The O/P frequency of a half wave rectifier is equal to the input frequency
B. The O/P frequency of a full wave rectifier is double to the input frequency
C. The regulation of an excellent rectifier should be zero.
D. ripple factor in the full wave rectifier is 1.2.
Choose the correct statements from the options given below:
In a rectifier the ripple factor can be expressed as
(a) \(\dfrac{I_{rms}}{I_{dc}}\) (b) \(\sqrt\dfrac{I_{dc}}{I_{rms}}\) (c) \(\sqrt{\left(\dfrac{I_{rms}}{I_{dc}}\right)^{2}-1}\) (d) \(\sqrt{1-\left(\dfrac{I_{rms}}{I_{dc}}\right)^{2}}\)
Which one of the above is correct ?
For a full-wave rectifier, which of the following statements are correct ?
(a) \(V_{dc}=\dfrac{2V_P}{\pi}\)
(b) \(f_{out}=2f_{in}\)
(c) \(V_{dc}=\dfrac{2\pi}{V_P}\)
(d) \(I_{dc}=\dfrac{I_m}{\sqrt{\pi}}\)
Options :
As compared to a full-wave rectifier using two diodes, the four diode bridge rectifier has the dominant advantage of :
In rectifiers :
(a) The efficiency of rectification is given by \(\eta=\dfrac{P_{ac}}{P_{dc}}\)
(b) The AC component on the output side : \(V_{ac}=\sqrt{V_{rms}^{2}-V_{dc}^{2}}\)
(c) Form factor is given by : \(FF=\dfrac{V_{dc}}{V_{rms}}\)
(d) Ripple factor is given by : \(RF=\sqrt{\left(\dfrac{V_{rms}}{V_{dc}}\right)^{2}-1}\)
Of these statements :
A half wave rectifier operates from 50 Hz supply and provides a peak output voltage of 60 V across the 600 Ω resistance. The value of capacitance for the capacitor filter would limit the peak to peak ripple voltage across load is 15 V :
Important Questions from Rectifier Circuits
PIV of a non conducting diode in a bridge rectifier is
The no-load output voltage of an ideal half wave rectifier is _______.
What is the minimum PIV required for a diode used in a full-wave rectifier circuit using a center-tapped transformer with a secondary voltage of 50V-0-50 V (rms)?
One of the following is a negative resistance device
Which of the following is NOT true for a rectifier?
