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Question

P is two times as efficient as Q. P is able to complete a piece of work in 40 days less than Q. Working together, the whole number of days taken by them to complete the work is:

(Round off to the nearest integer)

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is

27

Solving Work and Efficiency Problems: P and Q Together

This question involves a classic work and time problem, focusing on the concept of efficiency. Efficiency is inversely proportional to the time taken to complete a piece of work. If a person is more efficient, they take less time to complete the same amount of work.

Understanding Efficiency and Time

We are given that P is two times as efficient as Q. This means that for the same amount of work, P will take half the time that Q takes.

Let \( T_P \) be the time taken by P to complete the work alone, and \( T_Q \) be the time taken by Q to complete the work alone.

Since P is twice as efficient as Q, the time taken by P is half the time taken by Q:

\( T_P = \frac{1}{2} T_Q \)

Setting up Equations Based on the Problem

We are also told that P is able to complete the work in 40 days less than Q. This gives us another relationship between \( T_P \) and \( T_Q \):

\( T_P = T_Q - 40 \)

Finding Individual Times

Now we have two expressions for \( T_P \). We can set them equal to each other to solve for \( T_Q \):

\( \frac{1}{2} T_Q = T_Q - 40 \)

To solve for \( T_Q \), we can rearrange the equation:

\( 40 = T_Q - \frac{1}{2} T_Q \)

\( 40 = \left(1 - \frac{1}{2}\right) T_Q \)

\( 40 = \frac{1}{2} T_Q \)

Multiply both sides by 2:

\( T_Q = 40 \times 2 \)

\( T_Q = 80 \) days

Now that we have \( T_Q \), we can find \( T_P \) using either equation. Let's use \( T_P = T_Q - 40 \):

\( T_P = 80 - 40 \)

\( T_P = 40 \) days

Calculating Work Rate

The work rate of a person is the amount of work they complete in one day. If a person completes the entire work in \( T \) days, their work rate per day is \( \frac{1}{T} \) of the work.

  • P's work rate per day = \( \frac{1}{T_P} = \frac{1}{40} \)
  • Q's work rate per day = \( \frac{1}{T_Q} = \frac{1}{80} \)

Working Together

When P and Q work together, their work rates add up. The combined work rate per day is:

\( \text{Combined work rate} = \text{P's work rate} + \text{Q's work rate} \)

\( \text{Combined work rate} = \frac{1}{40} + \frac{1}{80} \)

To add these fractions, find a common denominator, which is 80:

\( \text{Combined work rate} = \frac{2}{80} + \frac{1}{80} \)

\( \text{Combined work rate} = \frac{3}{80} \)

This means that working together, P and Q complete \( \frac{3}{80} \) of the work in one day.

Finding Time Taken Together

The total time taken to complete the work when working together is the reciprocal of the combined work rate:

\( \text{Time together} = \frac{1}{\text{Combined work rate}} \)

\( \text{Time together} = \frac{1}{\frac{3}{80}} \)

\( \text{Time together} = \frac{80}{3} \) days

Rounding to the Nearest Integer

The question asks for the whole number of days taken, rounded off to the nearest integer. Let's calculate the value of \( \frac{80}{3} \):

\( \frac{80}{3} \approx 26.666... \)

Rounding 26.666... to the nearest integer gives 27.

So, working together, P and Q take approximately 27 days to complete the work.

Summary of Steps

  1. Used the efficiency ratio to relate the individual times of P and Q.
  2. Used the given time difference to create another equation relating their times.
  3. Solved the equations simultaneously to find the individual times \( T_P \) and \( T_Q \).
  4. Calculated the individual work rates per day.
  5. Added the individual work rates to find the combined work rate per day.
  6. Took the reciprocal of the combined work rate to find the total time taken when working together.
  7. Rounded the final answer to the nearest integer.
Individual Times and Work Rates
Person Individual Time (Days) Work Rate (Work per Day)
P 40 \( \frac{1}{40} \)
Q 80 \( \frac{1}{80} \)
P & Q Together \( \frac{80}{3} \approx 26.67 \) \( \frac{3}{80} \)

Revision Table: Work and Efficiency Concepts

Key Concepts in Work & Time Problems
Concept Description Relationship
Work The task to be completed (often considered as 1 unit). -
Time Duration taken to complete the work. Inversely proportional to Efficiency
Efficiency / Work Rate Amount of work done per unit of time. Efficiency \( \propto \frac{1}{\text{Time}} \)
Total Work Work Rate \( \times \) Time Often 1 unit for the whole task
Combined Work Rate Sum of individual work rates when people work together. \( R_{total} = R_1 + R_2 + ... \)

Additional Information: Alternative Method (LCM)

For work and time problems, you can sometimes assume a total amount of work based on the LCM (Least Common Multiple) of the individual times. This can help avoid fractions initially.

In this case, we found \( T_P = 40 \) days and \( T_Q = 80 \) days.

Let the total work be the LCM of 40 and 80, which is 80 units.

  • P completes 80 units in 40 days. P's work rate = \( \frac{80 \text{ units}}{40 \text{ days}} = 2 \) units/day.
  • Q completes 80 units in 80 days. Q's work rate = \( \frac{80 \text{ units}}{80 \text{ days}} = 1 \) unit/day.

Notice that P's rate (2 units/day) is indeed twice Q's rate (1 unit/day), matching the initial efficiency statement.

When P and Q work together, their combined rate is \( 2 + 1 = 3 \) units/day.

To complete 80 units of work at a combined rate of 3 units/day, the time taken is:

\( \text{Time together} = \frac{\text{Total Work}}{\text{Combined Rate}} = \frac{80 \text{ units}}{3 \text{ units/day}} = \frac{80}{3} \) days.

This gives the same result, \( \frac{80}{3} \approx 26.666... \) days, which rounds to 27 days. The LCM method can be useful for simplifying calculations with integers.

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Important Questions from Work Efficiency

  1. A and B working together can complete a job in 30 days. The ratio of their efficiencies is 3 : 2. In how many days can the faster person complete the job?

  2. A takes 15 days to complete \(\frac{5}{7} \)  of a work. With the help of B, they finish the whole work in 12 days. In how many days, B alone will complete the same work

  3. A alone can complete a work in 14 days and B alone can complete the same work in 21 days. A and B start the work together but A leaves the work after 4 days of the starting of work. In how many days B will complete the remaining work?

  4. For completing a certain work, A is 50% less efficient than B and B is 50% more efficient than C. Working together A, B and C can complete the work in 48 days. A alone can complete the same work in:

  5. 30 persons can do a piece of work in 24 days. How many more persons are required to complete the work in 20 days?

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