P is two times as efficient as Q. P is able to complete a piece of work in 40 days less than Q. Working together, the whole number of days taken by them to complete the work is: (Round off to the nearest integer)
27
This question involves a classic work and time problem, focusing on the concept of efficiency. Efficiency is inversely proportional to the time taken to complete a piece of work. If a person is more efficient, they take less time to complete the same amount of work.
We are given that P is two times as efficient as Q. This means that for the same amount of work, P will take half the time that Q takes.
Let \( T_P \) be the time taken by P to complete the work alone, and \( T_Q \) be the time taken by Q to complete the work alone.
Since P is twice as efficient as Q, the time taken by P is half the time taken by Q:
\( T_P = \frac{1}{2} T_Q \)
We are also told that P is able to complete the work in 40 days less than Q. This gives us another relationship between \( T_P \) and \( T_Q \):
\( T_P = T_Q - 40 \)
Now we have two expressions for \( T_P \). We can set them equal to each other to solve for \( T_Q \):
\( \frac{1}{2} T_Q = T_Q - 40 \)
To solve for \( T_Q \), we can rearrange the equation:
\( 40 = T_Q - \frac{1}{2} T_Q \)
\( 40 = \left(1 - \frac{1}{2}\right) T_Q \)
\( 40 = \frac{1}{2} T_Q \)
Multiply both sides by 2:
\( T_Q = 40 \times 2 \)
\( T_Q = 80 \) days
Now that we have \( T_Q \), we can find \( T_P \) using either equation. Let's use \( T_P = T_Q - 40 \):
\( T_P = 80 - 40 \)
\( T_P = 40 \) days
The work rate of a person is the amount of work they complete in one day. If a person completes the entire work in \( T \) days, their work rate per day is \( \frac{1}{T} \) of the work.
When P and Q work together, their work rates add up. The combined work rate per day is:
\( \text{Combined work rate} = \text{P's work rate} + \text{Q's work rate} \)
\( \text{Combined work rate} = \frac{1}{40} + \frac{1}{80} \)
To add these fractions, find a common denominator, which is 80:
\( \text{Combined work rate} = \frac{2}{80} + \frac{1}{80} \)
\( \text{Combined work rate} = \frac{3}{80} \)
This means that working together, P and Q complete \( \frac{3}{80} \) of the work in one day.
The total time taken to complete the work when working together is the reciprocal of the combined work rate:
\( \text{Time together} = \frac{1}{\text{Combined work rate}} \)
\( \text{Time together} = \frac{1}{\frac{3}{80}} \)
\( \text{Time together} = \frac{80}{3} \) days
The question asks for the whole number of days taken, rounded off to the nearest integer. Let's calculate the value of \( \frac{80}{3} \):
\( \frac{80}{3} \approx 26.666... \)
Rounding 26.666... to the nearest integer gives 27.
So, working together, P and Q take approximately 27 days to complete the work.
| Person | Individual Time (Days) | Work Rate (Work per Day) |
|---|---|---|
| P | 40 | \( \frac{1}{40} \) |
| Q | 80 | \( \frac{1}{80} \) |
| P & Q Together | \( \frac{80}{3} \approx 26.67 \) | \( \frac{3}{80} \) |
| Concept | Description | Relationship |
|---|---|---|
| Work | The task to be completed (often considered as 1 unit). | - |
| Time | Duration taken to complete the work. | Inversely proportional to Efficiency |
| Efficiency / Work Rate | Amount of work done per unit of time. | Efficiency \( \propto \frac{1}{\text{Time}} \) |
| Total Work | Work Rate \( \times \) Time | Often 1 unit for the whole task |
| Combined Work Rate | Sum of individual work rates when people work together. | \( R_{total} = R_1 + R_2 + ... \) |
For work and time problems, you can sometimes assume a total amount of work based on the LCM (Least Common Multiple) of the individual times. This can help avoid fractions initially.
In this case, we found \( T_P = 40 \) days and \( T_Q = 80 \) days.
Let the total work be the LCM of 40 and 80, which is 80 units.
Notice that P's rate (2 units/day) is indeed twice Q's rate (1 unit/day), matching the initial efficiency statement.
When P and Q work together, their combined rate is \( 2 + 1 = 3 \) units/day.
To complete 80 units of work at a combined rate of 3 units/day, the time taken is:
\( \text{Time together} = \frac{\text{Total Work}}{\text{Combined Rate}} = \frac{80 \text{ units}}{3 \text{ units/day}} = \frac{80}{3} \) days.
This gives the same result, \( \frac{80}{3} \approx 26.666... \) days, which rounds to 27 days. The LCM method can be useful for simplifying calculations with integers.
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