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Question

In a bipolar transistor, alpha is the ratio of:

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is collector current to emitter current

Understanding Alpha in Bipolar Transistors

A bipolar junction transistor (BJT) is a semiconductor device used for amplifying or switching electronic signals. It has three terminals: the base, the collector, and the emitter. The current flow within a BJT is primarily due to both electrons and holes, hence the term 'bipolar'.

Bipolar Transistor Current Ratios: Alpha and Beta

In the context of bipolar transistors, specific ratios of currents flowing through these terminals are defined to characterize the transistor's current gain. Two important current gain parameters are alpha (\(\alpha\)) and beta (\(\beta\)).

  • Alpha (\(\alpha\)) relates the collector current to the emitter current, typically in a common-base configuration.
  • Beta (\(\beta\)) relates the collector current to the base current, typically in a common-emitter configuration.

Defining Alpha (\(\alpha\))

Alpha (\(\alpha\)) is formally defined as the ratio of the change in collector current (\(\Delta I_C\)) to the change in emitter current (\(\Delta I_E\)) when the collector-base voltage (\(V_{CB}\)) is kept constant. For DC currents, it is often approximated as the ratio of the DC collector current (\(I_C\)) to the DC emitter current (\(I_E\)).

The formula for alpha is:

\(\alpha = \frac{I_C}{I_E}\)

Where:

  • \(I_C\) is the collector current.
  • \(I_E\) is the emitter current.

The emitter current (\(I_E\)) is the total current entering the emitter. It consists of the current flowing into the base (\(I_B\)) and the current flowing into the collector (\(I_C\)). This relationship is given by:

\(I_E = I_B + I_C\)

Since some current flows into the base, the collector current (\(I_C\)) is always slightly less than the emitter current (\(I_E\)). Therefore, the value of alpha (\(\alpha\)) is typically very close to, but less than, 1 (e.g., 0.95 to 0.99).

Analyzing the Options

Let's examine the given options based on the definition of alpha:

  • Option 1: collector current to emitter current

    This ratio is \(I_C / I_E\). This exactly matches the definition of alpha (\(\alpha\)).

  • Option 2: emitter current to collector current

    This ratio is \(I_E / I_C\). This is the inverse of alpha, \(1/\alpha\). Alpha is \(I_C / I_E\).

  • Option 3: base current to collector current

    This ratio is \(I_B / I_C\). This is the inverse of beta, \(1/\beta\). Beta is \(I_C / I_B\).

  • Option 4: collector current to base current

    This ratio is \(I_C / I_B\). This is the definition of beta (\(\beta\)), which is the common-emitter current gain.

Based on the standard definition, alpha in a bipolar transistor is the ratio of collector current to emitter current.

Revision Table: Bipolar Transistor Current Ratios

Parameter Ratio Formula Typical Value Configuration
Alpha (\(\alpha\)) Collector current to emitter current \(\alpha = \frac{I_C}{I_E}\) 0.95 - 0.99 Common Base
Beta (\(\beta\)) Collector current to base current \(\beta = \frac{I_C}{I_B}\) 50 - 300 Common Emitter

Additional Information: Alpha and Beta Relationship

Alpha (\(\alpha\)) and Beta (\(\beta\)) are related to each other. Knowing one allows you to calculate the other. The relationship comes from the current equation \(I_E = I_B + I_C\).

  • To find \(\alpha\) from \(\beta\):

    Start with \(\beta = \frac{I_C}{I_B}\), so \(I_B = \frac{I_C}{\beta}\).

    Substitute \(I_B\) into \(I_E = I_B + I_C\):

    \(I_E = \frac{I_C}{\beta} + I_C = I_C \left(\frac{1}{\beta} + 1\right) = I_C \left(\frac{1 + \beta}{\beta}\right)\)

    Now, find \(\alpha = \frac{I_C}{I_E}\):

    \(\alpha = \frac{I_C}{I_C \left(\frac{1 + \beta}{\beta}\right)} = \frac{\beta}{1 + \beta}\)

    So, the relationship is \(\alpha = \frac{\beta}{1 + \beta}\).

  • To find \(\beta\) from \(\alpha\):

    Rearrange \(\alpha = \frac{\beta}{1 + \beta}\):

    \(\alpha(1 + \beta) = \beta\)

    \(\alpha + \alpha\beta = \beta\)

    \(\alpha = \beta - \alpha\beta = \beta(1 - \alpha)\)

    \(\beta = \frac{\alpha}{1 - \alpha}\)

    So, the relationship is \(\beta = \frac{\alpha}{1 - \alpha}\).

These relationships highlight that alpha and beta are dependent parameters, characterizing the current gain of the bipolar transistor in different circuit configurations.

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