The LCM of two numbers in 48. Their ratio is 2:3 What is the sum of the numbers?
40
The question provides two key pieces of information about two numbers: their Least Common Multiple (LCM) is 48, and their ratio is 2:3. We need to find the sum of these two numbers.
When the ratio of two numbers is given as 2:3, it means the numbers can be represented as multiples of some common factor. Let this common factor be \(x\). Therefore, the two numbers can be written as:
Here, \(x\) is also the Highest Common Factor (HCF) of the two numbers, \(2x\) and \(3x\).
The LCM of two numbers \(a\) and \(b\) is given by the formula: \(\text{LCM}(a, b) = \frac{a \times b}{\text{HCF}(a, b)}\). In our case, the numbers are \(2x\) and \(3x\), and their HCF is \(x\).
So, the LCM of \(2x\) and \(3x\) is:
\[ \text{LCM}(2x, 3x) = \frac{(2x) \times (3x)}{x} = \frac{6x^2}{x} = 6x \]
Alternatively, we can think of the LCM of \(2x\) and \(3x\) as the product of their HCF and the remaining unique factors. The HCF is \(x\), the remaining factor from \(2x\) is 2, and the remaining factor from \(3x\) is 3. So, \(\text{LCM} = x \times 2 \times 3 = 6x\).
We are given that the LCM of the two numbers is 48. We have calculated the LCM in terms of \(x\) as \(6x\). Now, we can set up an equation:
\[ 6x = 48 \]
To find the value of \(x\), we divide both sides of the equation by 6:
\[ x = \frac{48}{6} \]
\[ x = 8 \]
So, the common factor \(x\) is 8. This is also the HCF of the two numbers.
Now that we know \(x = 8\), we can find the two numbers:
Let's quickly check if the LCM of 16 and 24 is indeed 48:
The question asks for the sum of the two numbers. The numbers are 16 and 24.
Sum = First Number + Second Number
Sum = \(16 + 24\)
Sum = \(40\)
The sum of the two numbers is 40.
| Description | Value |
|---|---|
| Ratio of numbers | 2:3 |
| Let numbers be | \(2x, 3x\) |
| Calculated LCM | \(6x\) |
| Given LCM | 48 |
| Equation | \(6x = 48\) |
| Value of \(x\) (HCF) | 8 |
| First number | \(2 \times 8 = 16\) |
| Second number | \(3 \times 8 = 24\) |
| Sum of numbers | \(16 + 24 = 40\) |
| Concept | Explanation | Application in Problem |
|---|---|---|
| Ratio | A comparison of two quantities. If the ratio is \(a:b\), numbers can be \(ax\) and \(bx\). | Numbers are \(2x\) and \(3x\). |
| HCF (Highest Common Factor) | The largest number that divides two or more numbers without leaving a remainder. | For \(2x\) and \(3x\), HCF is \(x\). |
| LCM (Least Common Multiple) | The smallest number that is a multiple of two or more numbers. | Given as 48. For \(2x\) and \(3x\), calculated as \(6x\). |
| Relation: LCM, HCF, Numbers | For two numbers \(a, b\): \(\text{LCM}(a, b) \times \text{HCF}(a, b) = a \times b\). | \(48 \times x = (2x) \times (3x)\), which gives \(48x = 6x^2\). If \(x \ne 0\), \(48 = 6x\), so \(x=8\). |
Understanding LCM and HCF is fundamental in number theory. Here are some additional points:
These concepts are crucial for solving various problems involving number properties and ratios.
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