Find the least common multiple of 56 and 50.
1400
The Least Common Multiple (LCM) of two or more numbers is the smallest positive integer that is a multiple of all the given numbers. It's often used when working with fractions or in problems involving cycles or repetitions.
There are several ways to find the LCM, but the prime factorization method is very common and reliable. Let's find the prime factorization of 56 and 50.
We break down 56 into its prime factors:
So, the prime factorization of 56 is \(2 \times 2 \times 2 \times 7\), which can be written in exponential form as \(2^3 \times 7^1\).
Now, let's break down 50 into its prime factors:
So, the prime factorization of 50 is \(2 \times 5 \times 5\), which can be written in exponential form as \(2^1 \times 5^2\).
To find the LCM of 56 and 50, we take the highest power of each prime factor that appears in either factorization. The prime factors involved are 2, 5, and 7.
Now, we multiply these highest powers together to get the LCM:
LCM(56, 50) = \(2^3 \times 5^2 \times 7^1 = 8 \times 25 \times 7\)
Let's calculate the product:
\(8 \times 25 = 200\)
\(200 \times 7 = 1400\)
So, the Least Common Multiple of 56 and 50 is 1400.
| Number | Prime Factorization |
|---|---|
| 56 | \(2^3 \times 7^1\) |
| 50 | \(2^1 \times 5^2\) |
| LCM(56, 50) | \(2^{\max(3,1)} \times 5^{\max(0,2)} \times 7^{\max(0,1)} = 2^3 \times 5^2 \times 7^1 = 8 \times 25 \times 7 = 1400\) |
Checking the options, we see that 1400 is one of the choices.
| Concept | Description | Relevance to LCM |
|---|---|---|
| Multiple | A number obtained by multiplying an integer by another integer. | LCM is the smallest common multiple. |
| Prime Number | A natural number greater than 1 that has no positive divisors other than 1 and itself. | Used in the prime factorization method. |
| Prime Factorization | Expressing a composite number as a product of its prime factors. | Essential step for calculating LCM using the prime factors method. |
| Highest Power | The largest exponent for a given prime factor in the factorizations of the numbers. | We use the highest power of each prime factor when calculating the LCM. |
The LCM is closely related to the Highest Common Factor (HCF) or Greatest Common Divisor (GCD). The HCF is the largest positive integer that divides two or more numbers without leaving a remainder.
There's a useful relationship between the LCM and HCF of two numbers, say 'a' and 'b':
\(\text{LCM}(a, b) \times \text{HCF}(a, b) = a \times b\)
Let's quickly find the HCF of 56 and 50 using their prime factorizations:
\(56 = 2^3 \times 7^1\)
\(50 = 2^1 \times 5^2\)
To find the HCF, we take the lowest power of each common prime factor. The only common prime factor is 2, and the lowest power is \(2^1\).
HCF(56, 50) = \(2^1 = 2\)
Now, let's check the relationship:
LCM(56, 50) \(\times\) HCF(56, 50) = \(1400 \times 2 = 2800\)
\(a \times b = 56 \times 50\)
\(56 \times 50 = 56 \times 5 \times 10 = 280 \times 10 = 2800\)
The relationship holds true: \(1400 \times 2 = 56 \times 50\), which is \(2800 = 2800\). This confirms our calculation of the LCM is likely correct.
What is HCF of 36, 72 and 126?
The HCF of 20, 28 and 48 is:
The HCF of 162, 54 and 135 is:
Find the LCM of 37, 111 and 148.
The HCF of two numbers is 12 and their LCM is 72. If one of the two numbers is 24, then the other number is:
The LCM of 56, 84 and 112 is:
The HCF of 56, 84 and 98 is:
The HCF of 36, 54 and 108 is:
Find the LCM of 34, 51 and 68.
The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?
What is the least number which when divided by 12,20 and 24 leaves in each case a remainder of 8?
Which of the following is a pair of co-primes?