If a box of mass 25 kg is pushed 15 m by a force of ‘F’ N and work done in the process is 480 J. Find F:
32
The question asks us to find the force applied to a box given the work done and the distance it was pushed. We are provided with the mass of the box, the distance it moved, and the amount of work done during the process. We need to use the relationship between work, force, and distance to solve this problem.
In physics, work done by a force on an object is defined as the product of the magnitude of the force and the distance moved by the object in the direction of the force. Mathematically, this is expressed by the formula:
\[W = F \times d\]
Where:
In this specific problem, we are given the work done (\(W\)) and the distance (\(d\)), and we need to find the force (\(F\)). We can rearrange the formula to solve for \(F\):
\[F = \frac{W}{d}\]
Let's list the given values from the question:
Now, we substitute these values into the rearranged formula for force:
\[F = \frac{W}{d}\]
\[F = \frac{480 \text{ J}}{15 \text{ m}}\]
To find the value of F, we perform the division:
\[F = \frac{480}{15}\]
We can perform this division:
| 480 ÷ 15 | = 32 |
So, the force \(F\) is 32 Newtons.
The calculated force required to push the box is 32 N.
| Concept | Definition/Formula | Unit |
|---|---|---|
| Work Done (\(W\)) | \(W = F \times d\) (when force and displacement are in the same direction) | Joules (J) |
| Force (\(F\)) | A push or a pull; \(F = \frac{W}{d}\) | Newtons (N) |
| Distance (\(d\)) | The length of the path covered; \(d = \frac{W}{F}\) | Meters (m) |
Work done is a scalar quantity, meaning it only has magnitude and no direction. The unit of work, the Joule (J), is defined as the work done when a force of one Newton moves an object through a distance of one meter (1 J = 1 N·m). Work is only done when a force causes displacement. If a force is applied but the object doesn't move, or if the force is applied perpendicular to the direction of motion, no work is done by that force.
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