Which of the following is Pythagorean triplet?
8, 15, 17
A Pythagorean triplet is a set of three positive integers, say $a$, $b$, and $c$, such that they satisfy the equation $a^2 + b^2 = c^2$. This relationship is derived from the Pythagorean theorem, which applies to right-angled triangles. In a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle, which is the longest side) is equal to the sum of the squares of the lengths of the other two sides. If $a$ and $b$ are the lengths of the two shorter sides (legs) and $c$ is the length of the hypotenuse, then $a^2 + b^2 = c^2$.
To determine which of the given options is a Pythagorean triplet, we need to check if the sum of the squares of the first two numbers equals the square of the third number for each set. The third number in each triplet should be the largest, representing the potential hypotenuse.
Here, $a=2$, $b=3$, and $c=7$. We check if $a^2 + b^2 = c^2$:
$a^2 + b^2 = 2^2 + 3^2 = 4 + 9 = 13$
$c^2 = 7^2 = 49$
Since $13 \neq 49$, the set (2, 3, 7) is not a Pythagorean triplet.
Here, $a=7$, $b=9$, and $c=11$. We check if $a^2 + b^2 = c^2$:
$a^2 + b^2 = 7^2 + 9^2 = 49 + 81 = 130$
$c^2 = 11^2 = 121$
Since $130 \neq 121$, the set (7, 9, 11) is not a Pythagorean triplet.
Here, $a=8$, $b=15$, and $c=17$. We check if $a^2 + b^2 = c^2$:
$a^2 + b^2 = 8^2 + 15^2 = 64 + 225 = 289$
$c^2 = 17^2 = 289$
Since $289 = 289$, the set (8, 15, 17) satisfies the Pythagorean theorem. Thus, it is a Pythagorean triplet.
Here, $a=17$, $b=21$, and $c=29$. We check if $a^2 + b^2 = c^2$:
$a^2 + b^2 = 17^2 + 21^2 = 289 + 441 = 730$
$c^2 = 29^2 = 841$
Since $730 \neq 841$, the set (17, 21, 29) is not a Pythagorean triplet.
| Triplet | $a^2 + b^2$ | $c^2$ | Pythagorean Triplet? |
|---|---|---|---|
| (2, 3, 7) | $2^2 + 3^2 = 4 + 9 = 13$ | $7^2 = 49$ | No |
| (7, 9, 11) | $7^2 + 9^2 = 49 + 81 = 130$ | $11^2 = 121$ | No |
| (8, 15, 17) | $8^2 + 15^2 = 64 + 225 = 289$ | $17^2 = 289$ | Yes |
| (17, 21, 29) | $17^2 + 21^2 = 289 + 441 = 730$ | $29^2 = 841$ | No |
Based on the checks, only the set (8, 15, 17) satisfies the condition $a^2 + b^2 = c^2$.
The Pythagorean triplet among the given options is (8, 15, 17).
| Concept | Definition | Formula |
|---|---|---|
| Pythagorean Theorem | Relates the sides of a right-angled triangle. | $a^2 + b^2 = c^2$ (where $a, b$ are legs, $c$ is hypotenuse) |
| Pythagorean Triplet | A set of three positive integers that satisfy the Pythagorean theorem. | $(a, b, c)$ where $a^2 + b^2 = c^2$ |
Here are some interesting points about Pythagorean triplets:
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