ΔABC is similar to ΔRST. If the ratio of altitudes of ΔABC : ΔRST is 1 : 4 and if RS = 6 cm, then find the length of AB.
1.5 cm
The problem involves two similar triangles, ΔABC and ΔRST. We are given information about the ratio of their corresponding altitudes and the length of one side in ΔRST. We need to find the length of the corresponding side in ΔABC.
When two triangles are similar, their corresponding angles are equal, and the ratio of their corresponding sides is constant. A crucial property of similar triangles is that the ratio of their corresponding altitudes, medians, and angle bisectors is equal to the ratio of their corresponding sides.
Given that ΔABC is similar to ΔRST, let \(h_1\) be the altitude of ΔABC corresponding to side AB, and \(h_2\) be the altitude of ΔRST corresponding to side RS. The problem states that the ratio of altitudes of ΔABC to ΔRST is 1 : 4.
So, we have:
\(\frac{\text{Altitude of } \Delta\text{ABC}}{\text{Altitude of } \Delta\text{RST}} = \frac{h_1}{h_2} = \frac{1}{4}\)
According to the property of similar triangles, the ratio of corresponding sides is equal to the ratio of corresponding altitudes. Side AB in ΔABC corresponds to side RS in ΔRST because the triangles are similar (ΔABC ~ ΔRST) in that specific order of vertices.
Therefore, we can write the proportion:
\(\frac{\text{Length of AB}}{\text{Length of RS}} = \frac{\text{Altitude of } \Delta\text{ABC}}{\text{Altitude of } \Delta\text{RST}}\)
Substituting the given values:
\(\frac{\text{AB}}{6 \text{ cm}} = \frac{1}{4}\)
Now we can solve the equation for AB:
\(\text{AB} = 6 \text{ cm} \times \frac{1}{4}\)
\(\text{AB} = \frac{6}{4} \text{ cm}\)
\(\text{AB} = \frac{3}{2} \text{ cm}\)
\(\text{AB} = 1.5 \text{ cm}\)
Thus, the length of side AB is 1.5 cm.
Here's a breakdown of the process:
| Property of Similar Triangles | Ratio |
|---|---|
| Ratio of Corresponding Sides | \(\frac{\text{AB}}{\text{RS}} = \frac{\text{BC}}{\text{ST}} = \frac{\text{AC}}{\text{RT}}\) |
| Ratio of Corresponding Altitudes | \(\frac{h_{ABC}}{h_{RST}} = \frac{1}{4}\) |
| Relationship | \(\frac{\text{AB}}{\text{RS}} = \frac{h_{ABC}}{h_{RST}}\) |
Understanding the properties of similar triangles is key to solving geometry problems like this one.
| Property | Description |
|---|---|
| Corresponding Angles | All pairs of corresponding angles are equal. (\(\angle A = \angle R\), \(\angle B = \angle S\), \(\angle C = \angle T\)) |
| Corresponding Sides | The ratio of all pairs of corresponding sides is constant. This constant ratio is called the scale factor. |
| Altitudes, Medians, Angle Bisectors | The ratio of corresponding altitudes, medians, and angle bisectors is equal to the ratio of corresponding sides (the scale factor). |
| Perimeters | The ratio of the perimeters is equal to the ratio of corresponding sides (the scale factor). |
| Areas | The ratio of the areas is equal to the square of the ratio of corresponding sides (the square of the scale factor). |
The scale factor is a very important concept when dealing with similar figures, including similar triangles. It is the constant ratio by which all linear dimensions of a figure are scaled to produce a similar figure.
Understanding the scale factor helps relate not just sides and altitudes, but also perimeters, medians, and angle bisectors.
Which of the following is Pythagorean triplet?
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