Find the L.C.M of 4/5, 2/3 and 5/7
20
To find the Least Common Multiple (L.C.M.) of fractions, we use a specific formula that relates the L.C.M. of the numerators and the Highest Common Factor (H.C.F.) of the denominators.
The formula is:
$$ \text{L.C.M. of fractions} = \frac{\text{L.C.M. of numerators}}{\text{H.C.F. of denominators}} $$
The given fractions are $\frac{4}{5}$, $\frac{2}{3}$, and $\frac{5}{7}$.
We need to find the L.C.M. of 4, 2, and 5.
Let's list the prime factors:
To find the L.C.M., we take the highest power of all prime factors that appear in any of the numbers.
L.C.M.(4, 2, 5) = $2^2 \times 5^1 = 4 \times 5 = 20$.
We need to find the H.C.F. of 5, 3, and 7.
Let's find the factors of each number:
The H.C.F. is the largest factor that is common to all the numbers. In this case, the only common factor is 1.
H.C.F.(5, 3, 7) = 1.
Now, we use the formula:
$$ \text{L.C.M. of } \frac{4}{5}, \frac{2}{3}, \frac{5}{7} = \frac{\text{L.C.M. of (4, 2, 5)}}{\text{H.C.F. of (5, 3, 7)}} $$
Substituting the values we found:
$$ \text{L.C.M. of fractions} = \frac{20}{1} = 20 $$
So, the L.C.M. of $\frac{4}{5}$, $\frac{2}{3}$, and $\frac{5}{7}$ is 20.
| Fractions | Numerators | Denominators | L.C.M. of Numerators | H.C.F. of Denominators | L.C.M. of Fractions |
|---|---|---|---|---|---|
| $\frac{4}{5}, \frac{2}{3}, \frac{5}{7}$ | 4, 2, 5 | 5, 3, 7 | L.C.M.(4, 2, 5) = 20 | H.C.F.(5, 3, 7) = 1 | $\frac{20}{1} = 20$ |
Let's quickly review the definitions of L.C.M. and H.C.F.
| Term | Definition | Example |
|---|---|---|
| L.C.M. (Least Common Multiple) | The smallest positive integer that is a multiple of two or more numbers. | L.C.M. of 4 and 6: Multiples of 4 are 4, 8, 12, 16... Multiples of 6 are 6, 12, 18... L.C.M.(4, 6) is 12. |
| H.C.F. (Highest Common Factor) | The largest positive integer that divides exactly into two or more numbers. Also known as G.C.F. (Greatest Common Factor). | H.C.F. of 12 and 18: Factors of 12 are 1, 2, 3, 4, 6, 12. Factors of 18 are 1, 2, 3, 6, 9, 18. Common factors are 1, 2, 3, 6. H.C.F.(12, 18) is 6. |
While this question is about the L.C.M. of fractions, it's useful to know how to find the H.C.F. of fractions as well. The formula is similar but inverted:
$$ \text{H.C.F. of fractions} = \frac{\text{H.C.F. of numerators}}{\text{L.C.M. of denominators}} $$
For the fractions $\frac{4}{5}$, $\frac{2}{3}$, $\frac{5}{7}$:
So, the H.C.F. of $\frac{4}{5}$, $\frac{2}{3}$, and $\frac{5}{7}$ would be $\frac{1}{105}$.
Understanding both formulas helps in solving problems involving either L.C.M. or H.C.F. of fractions.
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