The LCM of the three numbers 16, 28 and 42 is:
336
The question asks us to find the Least Common Multiple (LCM) of the numbers 16, 28, and 42. The LCM is the smallest positive integer that is a multiple of all the given numbers. One common method to find the LCM is by using prime factorization.
Here are the steps involved:
Let's find the prime factors for each number:
We can divide 16 by the smallest prime number, 2, repeatedly:
$16 \div 2 = 8$
$8 \div 2 = 4$
$4 \div 2 = 2$
$2 \div 2 = 1$
So, the prime factorization of 16 is $2 \times 2 \times 2 \times 2 = 2^4$.
Divide 28 by the smallest prime number, 2:
$28 \div 2 = 14$
$14 \div 2 = 7$
Now, 7 is a prime number, so we stop.
So, the prime factorization of 28 is $2 \times 2 \times 7 = 2^2 \times 7^1$.
Divide 42 by the smallest prime number, 2:
$42 \div 2 = 21$
Now, 21 is not divisible by 2, but it is divisible by the next prime number, 3:
$21 \div 3 = 7$
Again, 7 is a prime number, so we stop.
So, the prime factorization of 42 is $2 \times 3 \times 7 = 2^1 \times 3^1 \times 7^1$.
Now, let's look at the prime factors and their highest powers across the numbers 16, 28, and 42:
| Prime Factor | Power in 16 ($2^4$) | Power in 28 ($2^2 \times 7^1$) | Power in 42 ($2^1 \times 3^1 \times 7^1$) | Highest Power |
|---|---|---|---|---|
| 2 | $2^4$ | $2^2$ | $2^1$ | $2^4$ |
| 3 | $3^0$ (implicit) | $3^0$ (implicit) | $3^1$ | $3^1$ |
| 7 | $7^0$ (implicit) | $7^1$ | $7^1$ | $7^1$ |
To find the LCM, we multiply the highest powers of all distinct prime factors (2, 3, and 7) we identified:
LCM = (Highest power of 2) $\times$ (Highest power of 3) $\times$ (Highest power of 7)
LCM = $2^4 \times 3^1 \times 7^1$
LCM = $16 \times 3 \times 7$
LCM = $48 \times 7$
LCM = $336$
The Least Common Multiple of 16, 28, and 42 is 336.
| Concept | Definition | How to Find (using Prime Factors) | Example (LCM of 12, 18) | Example (HCF of 12, 18) |
|---|---|---|---|---|
| LCM (Least Common Multiple) | The smallest positive integer divisible by all given numbers. | Take the highest power of each distinct prime factor present in any number's factorization and multiply them. | $12 = 2^2 \times 3^1$ $18 = 2^1 \times 3^2$ LCM = $2^2 \times 3^2 = 4 \times 9 = 36$ |
- |
| HCF (Highest Common Factor) or GCD (Greatest Common Divisor) | The largest positive integer that divides all given numbers without leaving a remainder. | Take the lowest power of each common prime factor present in all numbers' factorizations and multiply them. | - | $12 = 2^2 \times 3^1$ $18 = 2^1 \times 3^2$ Common factors: 2, 3 Lowest powers: $2^1, 3^1$ HCF = $2^1 \times 3^1 = 2 \times 3 = 6$ |
Besides prime factorization, another method to find the LCM is listing multiples:
The smallest number that appears in all three lists is 336. This confirms our result from the prime factorization method.
The relationship between LCM and HCF for two numbers 'a' and 'b' is given by: $a \times b = \text{LCM}(a, b) \times \text{HCF}(a, b)$. This relationship does not directly extend to three numbers in the same simple product form, but prime factorization remains a reliable method for any number of integers.
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