If three numbers are in ratio of 3 : 5 : 7 and their LCM is 2415, what is the difference between the second number and the first number?
46
The question provides three numbers that are in a specific ratio, which is 3 : 5 : 7. We are also given that the Least Common Multiple (LCM) of these three numbers is 2415. Our goal is to find the difference between the second number and the first number.
When numbers are in a ratio like 3 : 5 : 7, we can represent them using a common factor. Let this common factor be \(x\). So, the three numbers can be written as:
To find the LCM of the three numbers \(3x\), \(5x\), and \(7x\), we need to consider the LCM of the coefficients (3, 5, and 7) and the common factor \(x\).
Let's find the LCM of 3, 5, and 7. Since 3, 5, and 7 are all prime numbers, their LCM is simply their product.
\(\text{LCM}(3, 5, 7) = 3 \times 5 \times 7 = 105\)
The LCM of the three numbers \(3x\), \(5x\), and \(7x\) will therefore be the LCM of their coefficients multiplied by the common factor \(x\).
\(\text{LCM}(3x, 5x, 7x) = \text{LCM}(3, 5, 7) \times x = 105x\)
We are given that the LCM of the three numbers is 2415. We have also determined that the LCM can be represented as \(105x\).
So, we can set up an equation:
\(105x = 2415\)
To find the value of \(x\), we need to divide 2415 by 105.
\(x = \frac{2415}{105}\)
Let's perform the division:
| Step | Calculation |
|---|---|
| Divide 2415 by 105 | \(2415 \div 105 = 23\) |
So, the common factor \(x\) is 23.
Now that we have the value of \(x\), we can find the three numbers:
Let's quickly verify if the LCM of 69, 115, and 161 is indeed 2415.
The common factor is 23, and the unique factors are 3, 5, and 7. The LCM is the product of the highest powers of all prime factors involved.
\(\text{LCM}(69, 115, 161) = 3 \times 5 \times 7 \times 23 = 105 \times 23 = 2415\)
This matches the given information, so our numbers are correct.
The question asks for the difference between the second number and the first number.
Difference = Second number - First number
Difference = \(115 - 69\)
Difference = 46
The difference between the second number and the first number is 46.
| Concept | Description | Application in Problem |
|---|---|---|
| Ratio | A comparison of two or more quantities. Represented as \(a:b\) or \(a:b:c\). Numbers in ratio \(a:b:c\) can be written as \(ax, bx, cx\) where \(x\) is a common factor. | The numbers are in ratio 3:5:7, so they are \(3x, 5x, 7x\). |
| Least Common Multiple (LCM) | The smallest positive integer that is divisible by all the given numbers. | The LCM of \(3x, 5x, 7x\) is calculated. Since 3, 5, 7 are coprime, \(\text{LCM}(3, 5, 7) = 3 \times 5 \times 7 = 105\). The LCM of the numbers is \(105x\). |
| Solving for Unknown | Using the given information to form an equation and find the value of the unknown variable (\(x\)). | The given LCM is 2415. We set \(105x = 2415\) and solve for \(x\). |
For two numbers \(a\) and \(b\), the product of their Highest Common Factor (HCF) and LCM is equal to the product of the numbers themselves:
\(\text{HCF}(a, b) \times \text{LCM}(a, b) = a \times b\)
For three numbers, there isn't a simple direct formula like the one for two numbers. However, understanding the prime factorization of numbers is key to finding both HCF and LCM for any set of numbers.
In this problem, the numbers are \(3x, 5x, 7x\). Notice that \(x\) is the Highest Common Factor (HCF) of these three numbers because 3, 5, and 7 are coprime (have no common factors other than 1). So, HCF(\(3x, 5x, 7x\)) = \(x\). The LCM is \(\text{LCM}(3, 5, 7) \times x = 105x\).
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