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Question

Find the potential difference (in V) across a resistance of 2.5 kΩ through which a 2 mA current flows.

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is

5

Understanding Potential Difference Calculation

This problem asks us to find the potential difference across a resistor when we know its resistance and the current flowing through it. This is a classic application of Ohm's Law, a fundamental principle in electrical circuits.

Applying Ohm's Law to Find Voltage

Ohm's Law describes the relationship between voltage (potential difference), current, and resistance in an electrical circuit. It is stated as:

\[V = I \times R\]

Where:

  • \(V\) is the potential difference (voltage) measured in Volts (V).
  • \(I\) is the current measured in Amperes (A).
  • \(R\) is the resistance measured in Ohms (\(\Omega\)).

Given Values and Units Conversion

We are given the following values:

  • Resistance (\(R\)) = 2.5 k\(\Omega\)
  • Current (\(I\)) = 2 mA

Before we can use Ohm's Law, we need to ensure all units are in their base SI forms (Ohms for resistance, Amperes for current). The given values are in kiloohms (k\(\Omega\)) and milliamperes (mA), so we need to convert them:

  • 1 k\(\Omega\) = \(10^3 \Omega\)
  • 1 mA = \(10^{-3}\) A

Converting the given values:

  • Resistance \(R = 2.5 \text{ k}\Omega = 2.5 \times 10^3 \Omega\)
  • Current \(I = 2 \text{ mA} = 2 \times 10^{-3} \text{ A}\)
Quantity Given Value SI Unit Converted Value (SI Units)
Resistance (\(R\)) 2.5 k\(\Omega\) \(\Omega\) \(2.5 \times 10^3 \Omega\)
Current (\(I\)) 2 mA A \(2 \times 10^{-3}\) A

Step-by-Step Potential Difference Calculation

Now that we have the resistance and current in the correct units, we can calculate the potential difference (\(V\)) using Ohm's Law:

\[V = I \times R\]

Substitute the converted values into the formula:

\[V = (2 \times 10^{-3} \text{ A}) \times (2.5 \times 10^3 \Omega)\]

Multiply the numerical parts and the powers of ten separately:

\[V = (2 \times 2.5) \times (10^{-3} \times 10^3) \text{ V}\]

\[V = 5 \times 10^{(-3 + 3)} \text{ V}\]

\[V = 5 \times 10^0 \text{ V}\]

Since \(10^0 = 1\):

\[V = 5 \times 1 \text{ V}\]

\[V = 5 \text{ V}\]

The potential difference across the 2.5 k\(\Omega\) resistance is 5 V.

Conclusion: Potential Difference Result

Based on the calculation using Ohm's Law, the potential difference across the resistance is 5 Volts. This matches one of the provided options for the potential difference.

Revision Table: Key Formulas and Units

Concept Formula Units
Ohm's Law \(V = I \times R\) Volts (V), Amperes (A), Ohms (\(\Omega\))
Potential Difference (Voltage) \(V\) Volts (V)
Current \(I\) Amperes (A)
Resistance \(R\) Ohms (\(\Omega\))

Additional Information: Understanding Ohm's Law and Units

Ohm's Law is a linear relationship between voltage and current for many materials, especially conductors like metals, under constant temperature. It essentially states that the current through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them.

Understanding unit prefixes like 'kilo' (k) and 'milli' (m) is crucial in physics and engineering calculations. They represent powers of 10:

  • kilo (k) means \(10^3\) (one thousand)
  • milli (m) means \(10^{-3}\) (one thousandth)

Always convert values with prefixes to the base unit before performing calculations using formulas like Ohm's Law to avoid errors.

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Similar Questions

  1. _____ states that the electric current flowing through a metallic wire is directly proportional to the potential difference 'V' across its ends provided its temperature remains the same.
  2. Fill in the blank with the most appropriate option.

    18 volts = _________ × 3 ohms.

  3. According to Ohm's Law, which of the following is true?

  4. According to Ohm’s law, if current (I) increases and potential difference (V) remains constant, then:


Important Questions from Ohm’s Law

  1. Which one of the following statements regarding Ohm's law is not correct?

  2. A simple circuit contains a 12 V battery and a bulb having 24-ohm resistance. When you turn on the switch, the ammeter connected to the circuit would read

  3. Which one of the following devices is non-ohmic?

  4. Three resistors having resistances in the ratio 1 : 2 : 3 are in parallel. The current through the resistors are in the ratio

  5. Ohm’s Law is applicable to

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